Skip to content
Open
Changes from 2 commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
61 changes: 61 additions & 0 deletions maths/laplace_transformation.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,61 @@
"""
The Laplace Transform is defined as: L{f(t)} = integral from 0 to infinity of e^(-st) * f(t) dt.

Check failure on line 2 in maths/laplace_transformation.py

View workflow job for this annotation

GitHub Actions / ruff

ruff (E501)

maths/laplace_transformation.py:2:89: E501 Line too long (96 > 88)

Wiki: https://en.wikipedia.org/wiki/Laplace_transform

"""

import numpy as np


def laplace_transform(
function_values: np.ndarray, s_value: float, delta_t: float
) -> float:
Comment thread
Tushar-R-Tyagi marked this conversation as resolved.
"""
Calculate the numerical Laplace Transform of a function given its values over time.

Args:
function_values: A numpy array of the function values f(t).
s_value: The complex frequency parameter 's' (modeled here as a float).
delta_t: The time step between samples.

Returns:
The approximate value of the Laplace transform at s_value.
Comment thread
Tushar-R-Tyagi marked this conversation as resolved.
Outdated

Example: For f(t) = 1, the Laplace transform L{1} = 1/s.
If s = 2, L{1} should be 0.5.

>>> t = np.linspace(0, 50, 10000)
>>> f_t = np.ones_like(t) # f(t) = 1
>>> res = laplace_transform(f_t, s_value=2.0, delta_t=50/10000)
>>> abs(res - 0.5) < 1e-3
Comment thread
Tushar-R-Tyagi marked this conversation as resolved.
True

Example: For f(t) = e^(-t), the Laplace transform L{e^-t} = 1/(s+1).
If s = 1, L{e^-t} should be 0.5.

>>> t = np.linspace(0, 50, 10000)
>>> f_t = np.exp(-t)
>>> res = laplace_transform(f_t, s_value=1.0, delta_t=50/10000)
>>> abs(res - 0.5) < 1e-3
Comment thread
Tushar-R-Tyagi marked this conversation as resolved.
True
"""
if s_value < 0:
raise ValueError("s_value must be non-negative for convergence.")
Copy link

Copilot AI Apr 28, 2026

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

The convergence check if s_value < 0: raise ... is not generally correct for the Laplace transform (e.g., for f(t)=e^{-t}, the transform converges for Re(s) > -1). Also, since this implementation integrates over a finite sampled window, negative s_value won't inherently diverge. Consider removing this restriction, or (if you keep it) documenting it as a deliberate limitation rather than a convergence requirement.

Copilot uses AI. Check for mistakes.

# Time vector corresponding to the function values
time_vector = np.arange(len(function_values)) * delta_t

# The integrand: f(t) * e^(-s*t)
integrand = function_values * np.exp(-s_value * time_vector)

# Numerical integration using the trapezoidal rule
result = np.trapezoid(integrand, dx=delta_t)

return float(result)


if __name__ == "__main__":
import doctest

doctest.testmod()
Loading