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feat: add numerical laplace transform #14602
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| """ | ||
| The Laplace Transform is defined as: L{f(t)} = integral from 0 to infinity of e^(-st) * f(t) dt. | ||
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| Wiki: https://en.wikipedia.org/wiki/Laplace_transform | ||
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| """ | ||
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| import numpy as np | ||
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| def laplace_transform( | ||
| function_values: np.ndarray, s_value: float, delta_t: float | ||
| ) -> float: | ||
| """ | ||
| Calculate the numerical Laplace Transform of a function given its values over time. | ||
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| Args: | ||
| function_values: A numpy array of the function values f(t). | ||
| s_value: The complex frequency parameter 's' (modeled here as a float). | ||
| delta_t: The time step between samples. | ||
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| Returns: | ||
| The approximate value of the Laplace transform at s_value. | ||
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| Example: For f(t) = 1, the Laplace transform L{1} = 1/s. | ||
| If s = 2, L{1} should be 0.5. | ||
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| >>> t = np.linspace(0, 50, 10000) | ||
| >>> f_t = np.ones_like(t) # f(t) = 1 | ||
| >>> res = laplace_transform(f_t, s_value=2.0, delta_t=50/10000) | ||
| >>> abs(res - 0.5) < 1e-3 | ||
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| True | ||
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| Example: For f(t) = e^(-t), the Laplace transform L{e^-t} = 1/(s+1). | ||
| If s = 1, L{e^-t} should be 0.5. | ||
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| >>> t = np.linspace(0, 50, 10000) | ||
| >>> f_t = np.exp(-t) | ||
| >>> res = laplace_transform(f_t, s_value=1.0, delta_t=50/10000) | ||
| >>> abs(res - 0.5) < 1e-3 | ||
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| True | ||
| """ | ||
| if s_value < 0: | ||
| raise ValueError("s_value must be non-negative for convergence.") | ||
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| # Time vector corresponding to the function values | ||
| time_vector = np.arange(len(function_values)) * delta_t | ||
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| # The integrand: f(t) * e^(-s*t) | ||
| integrand = function_values * np.exp(-s_value * time_vector) | ||
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| # Numerical integration using the trapezoidal rule | ||
| result = np.trapezoid(integrand, dx=delta_t) | ||
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| return float(result) | ||
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| if __name__ == "__main__": | ||
| import doctest | ||
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| doctest.testmod() | ||
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