week6 lab3 from Xingyu

solutions.sql

@@ -1 +1,124 @@
--- Add you solution queries below:
+use sakila;
+
+-- 1
+select 
+	count(i.inventory_id) as num_copies
+from inventory i
+left join film f on f.film_id = i.film_id
+where f.title = 'Hunchback Impossible';
+
+-- 2
+select 
+	distinct title, 
+    length
+from film
+where length > (select avg(length) from film);
+
+-- 3
+select 
+	concat(first_name, ' ', last_name) as actor_name
+from (
+	select 
+		f.film_id,
+        f.title,
+        a.first_name,
+        a.last_name
+	from film f
+	left join film_actor fa on fa.film_id = f.film_id
+    left join actor a on a.actor_id = fa.actor_id
+    where f.title = 'Alone Trip'
+) alone_trip;
+
+-- 4
+select
+	distinct title
+from (
+	select
+		f.film_id,
+        f.title
+    from film f
+    join film_category fc on fc.film_id = f.film_id
+    join category c on c.category_id = fc.category_id
+    where c.`name` = 'Family'
+
+) family_movies;
+
+-- 5
+select 
+	concat(first_name, ' ', last_name) as customer_name,
+    email
+from (
+	select 
+		c.first_name,
+        c.last_name,
+        c.email
+	from customer c
+    join address a on a.address_id = c.address_id
+    join city ci on a.city_id = ci.city_id
+    join country co on co.country_id = ci.country_id
+    where co.country = 'Canada'
+) Canadian_customers;
+
+-- 6
+select 
+	fa.film_id,
+    f.title
+from film_actor fa
+left join film f on fa.film_id = f.film_id
+where fa.actor_id in(
+	select actor_id
+	from(
+		select
+			actor_id,
+			count(film_id) as num_movies
+		from film_actor
+		group by actor_id
+		order by num_movies desc
+		limit 1
+	) prolific_actor
+);
+
+-- 7
+select
+	f.title,
+    p.customer_id
+from film f
+left join inventory i on i.film_id = f.film_id
+left join rental r on r.inventory_id = i.inventory_id
+left join payment p on p.rental_id = r.rental_id
+where p.customer_id in (
+	select customer_id 
+	from (
+		select 
+			customer_id,
+			sum(amount) as total_spent
+		from payment
+		group by customer_id
+		order by total_spent desc
+		limit 1
+	) most_profitable_customer
+);
+
+-- 8
+select
+	customer_id as client_id,
+    sum(amount) as total_amount_spent
+from payment
+group by client_id
+having total_amount_spent > (
+	select 
+		avg(total_spent) as avg_total_spent
+	from (
+		select
+			customer_id,
+			sum(amount) as total_spent
+		from payment
+		group by customer_id
+	) total_spent_each_customer
+);
+
+
+
+
+
+