algorihm [fiqqar] adding new algorithm {concatination array}

concate_array/arr.py

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+from typing import List
+
+class Solution:
+    def getConcatenation(self, nums: List[int]) -> List[int]:
+        l = len(nums)
+        res = [0] * (2 * l)
+        for i in range(l):
+            res[i] = nums[i]
+            res[i+l] = nums[i]
+        return res
+

concate_array/readme.md

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+<h2>>Concatenation of Array</a></h2><h3>Easy</h3><hr><p>Given an integer array</code> of length <code>n</code>, you want to create an array <code>ans</code> of length <code>2n</code> where <code>ans[i] == nums[i]</code> and <code>ans[i + n] == nums[i]</code> for <code>0 &lt;= i &lt; n</code> (<strong>0-indexed</strong>).</p>
+
+<p>Specifically, <code>ans</code> is the <strong>concatenation</strong> of two <code>nums</code> arrays.</p>
+
+<p>Return <em>the array </em><code>ans</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [1,2,1]
+<strong>Output:</strong> [1,2,1,1,2,1]
+<strong>Explanation:</strong> The array ans is formed as follows:
+- ans = [nums[0],nums[1],nums[2],nums[0],nums[1],nums[2]]
+- ans = [1,2,1,1,2,1]</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [1,3,2,1]
+<strong>Output:</strong> [1,3,2,1,1,3,2,1]
+<strong>Explanation:</strong> The array ans is formed as follows:
+- ans = [nums[0],nums[1],nums[2],nums[3],nums[0],nums[1],nums[2],nums[3]]
+- ans = [1,3,2,1,1,3,2,1]
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>n == nums.length</code></li>
+	<li><code>1 &lt;= n &lt;= 1000</code></li>
+	<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>
+</ul>