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432 changes: 432 additions & 0 deletions app/visualizer/trees/bst/deletion/animation.jsx

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180 changes: 180 additions & 0 deletions app/visualizer/trees/bst/deletion/code.js
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const codeExamples = {
javascript: `// Binary Search Tree node
class TreeNode {
constructor(value) {
this.value = value;
this.left = null;
this.right = null;
}
}

// Delete a value from the BST
function deleteNode(node, value) {
if (node === null) return null;

if (value < node.value) {
node.left = deleteNode(node.left, value);
return node;
}
if (value > node.value) {
node.right = deleteNode(node.right, value);
return node;
}

// Found the node to delete
if (node.left === null && node.right === null) return null; // Case 1: leaf
if (node.left === null) return node.right; // Case 2: only right child
if (node.right === null) return node.left; // Case 2: only left child

// Case 3: two children — find in-order successor (min of right subtree)
let successor = node.right;
while (successor.left !== null) successor = successor.left;

node.value = successor.value;
node.right = deleteNode(node.right, successor.value);
return node;
}

// Usage example
let root = null;
[8, 3, 12, 10, 14].forEach((value) => {
root = insertNode(root, value); // see BST Insertion for insertNode
});
root = deleteNode(root, 8);`,

python: `# Binary Search Tree node
class TreeNode:
def __init__(self, value):
self.value = value
self.left = None
self.right = None

# Delete a value from the BST
def delete_node(node, value):
if node is None:
return None

if value < node.value:
node.left = delete_node(node.left, value)
return node
if value > node.value:
node.right = delete_node(node.right, value)
return node

# Found the node to delete
if node.left is None and node.right is None:
return None # Case 1: leaf
if node.left is None:
return node.right # Case 2: only right child
if node.right is None:
return node.left # Case 2: only left child

# Case 3: two children — find in-order successor (min of right subtree)
successor = node.right
while successor.left is not None:
successor = successor.left

node.value = successor.value
node.right = delete_node(node.right, successor.value)
return node

# Usage example
root = None
for value in [8, 3, 12, 10, 14]:
root = insert_node(root, value) # see BST Insertion for insert_node
root = delete_node(root, 8)`,

c: `#include <stdio.h>
#include <stdlib.h>

typedef struct TreeNode {
int value;
struct TreeNode *left, *right;
} TreeNode;

TreeNode* newNode(int value) {
TreeNode* node = (TreeNode*)malloc(sizeof(TreeNode));
node->value = value;
node->left = node->right = NULL;
return node;
}

// Delete a value from the BST
TreeNode* deleteNode(TreeNode* node, int value) {
if (node == NULL) return NULL;

if (value < node->value) {
node->left = deleteNode(node->left, value);
return node;
}
if (value > node->value) {
node->right = deleteNode(node->right, value);
return node;
}

// Found the node to delete
if (node->left == NULL && node->right == NULL) {
free(node);
return NULL; // Case 1: leaf
}
if (node->left == NULL) {
TreeNode* right = node->right;
free(node);
return right; // Case 2: only right child
}
if (node->right == NULL) {
TreeNode* left = node->left;
free(node);
return left; // Case 2: only left child
}

// Case 3: two children — find in-order successor (min of right subtree)
TreeNode* successor = node->right;
while (successor->left != NULL) successor = successor->left;

node->value = successor->value;
node->right = deleteNode(node->right, successor->value);
return node;
}`,

java: `class TreeNode {
int value;
TreeNode left, right;

TreeNode(int value) {
this.value = value;
}
}

public class BstDeletion {

// Delete a value from the BST
static TreeNode deleteNode(TreeNode node, int value) {
if (node == null) return null;

if (value < node.value) {
node.left = deleteNode(node.left, value);
return node;
}
if (value > node.value) {
node.right = deleteNode(node.right, value);
return node;
}

// Found the node to delete
if (node.left == null && node.right == null) return null; // Case 1: leaf
if (node.left == null) return node.right; // Case 2: only right child
if (node.right == null) return node.left; // Case 2: only left child

// Case 3: two children — find in-order successor (min of right subtree)
TreeNode successor = node.right;
while (successor.left != null) successor = successor.left;

node.value = successor.value;
node.right = deleteNode(node.right, successor.value);
return node;
}
}`,
};

export default codeExamples;
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