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124 changes: 90 additions & 34 deletions 02_activities/assignments/Microcredential_Cohort/assignment1.sql
Original file line number Diff line number Diff line change
Expand Up @@ -6,31 +6,38 @@
--SELECT
/* 1. Write a query that returns everything in the customer table. */
--QUERY 1




SELECT * FROM customer;
--END QUERY


/* 2. Write a query that displays all of the columns and 10 rows from the customer table,
sorted by customer_last_name, then customer_first_ name. */
--QUERY 2



SELECT *
FROM customer
ORDER BY customer_first_name ASC, customer_last_name ASC
LIMIT 10;

-- QUALITY CHECKING: trying the DESC version to see if organizes names from Z to A
/*
SELECT *
FROM customer
ORDER BY customer_first_name DESC, customer_last_name DESC
LIMIT 10
*/

--END QUERY


--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9.
Limit to 25 rows of output. */
--QUERY 3




--QUERY 3
SELECT * FROM customer_purchases
WHERE product_id == 1
OR product_id == 4;
--END QUERY


Expand All @@ -42,10 +49,20 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
Limit to 25 rows of output.
*/
--QUERY 4




SELECT *
,(quantity* cost_to_customer_per_qty) as price
FROM customer_purchases
WHERE customer_id BETWEEN 8 AND 10
LIMIT 25;

/* CAN ALSO BE WRITTEN AS:
SELECT *
,(quantity* cost_to_customer_per_qty) as price
FROM customer_purchases
WHERE customer_id > 7
AND customer_id < 11
LIMIT 25;
*/
--END QUERY


Expand All @@ -55,10 +72,13 @@ Using the product table, write a query that outputs the product_id and product_n
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
--QUERY 5




SELECT product_id, product_name, prod_qty_type_condensed
FROM (
SELECT product_id, product_name, product_qty_type
,CASE WHEN product_qty_type= 'unit' THEN 'unit'
ELSE 'bulk' END as prod_qty_type_condensed
FROM product
);
--END QUERY


Expand All @@ -67,8 +87,16 @@ add a column to the previous query called pepper_flag that outputs a 1 if the pr
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
--QUERY 6

SELECT product_id, product_name, pepper_flag, prod_qty_type_condensed
FROM (
SELECT product_id, product_name, product_qty_type -- THESE ARE THE COLUMNS NEEDED
,CASE WHEN product_qty_type= 'unit' THEN 'unit'
ELSE 'bulk' END AS prod_qty_type_condensed


, CASE WHEN product_name LIKE '%pepper%' THEN 1 -- LIKE MEANS TEXT IS SEARCHED FOR PEPPER REGARDLESS OF CAPITALIZATION
ELSE 0 END AS pepper_flag
FROM product
);

--END QUERY

Expand All @@ -78,37 +106,50 @@ contains the word “pepper” (regardless of capitalization), and otherwise out
vendor_id field they both have in common, and sorts the result by market_date, then vendor_name.
Limit to 24 rows of output. */
--QUERY 7




SELECT vendor.vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name, -- originating from vendor table
vendor_booth_assignments.vendor_id, booth_number, market_date -- originating from vendor booth assignments
FROM vendor
INNER JOIN vendor_booth_assignments
ON vendor.vendor_id = vendor_booth_assignments.vendor_id
ORDER BY market_date ASC, vendor_name ASC;
--END QUERY



/* SECTION 3 */

-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */
--QUERY 8

-- This version only lists the vendor id
SELECT vendor_id, COUNT(booth_number) as Num_times_rented
FROM vendor_booth_assignments
GROUP BY vendor_id;


-- This version lists the vendor id and the corresponding name
SELECT COUNT(booth_number) as Num_times_rented, vendor.vendor_id, vendor.vendor_name
FROM vendor
INNER JOIN vendor_booth_assignments -- inner join returns values on vendor_id that are matching in both tables
ON vendor.vendor_id = vendor_booth_assignments.vendor_id
GROUP BY vendor.vendor_id;

--END QUERY


/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
--QUERY 9




SELECT customer.customer_id, customer_first_name, customer_last_name,
SUM(quantity* cost_to_customer_per_qty) as total_spend -- AGGREGATE FUNCTION
FROM customer
INNER JOIN customer_purchases -- JOINING 2 TABLES
ON customer.customer_id = customer_purchases.customer_id
GROUP BY customer.customer_id
HAVING total_spend > 2000 -- HAVING KEY WORD
ORDER BY customer_first_name ASC, customer_last_name;
--END QUERY


Expand All @@ -125,7 +166,14 @@ VALUES(col1,col2,col3,col4,col5)
*/
--QUERY 10

DROP TABLE IF EXISTS temp.new_vendor;

CREATE TABLE temp.new_vendor AS
SELECT *
FROM vendor;

INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
VALUES (10, 'Thomass Superfood Store', 'a Fresh Focused store', 'Thomas', 'Rosenthal');


--END QUERY
Expand All @@ -139,8 +187,11 @@ and year are!
Limit to 25 rows of output. */
--QUERY 11



SELECT customer_id
,strftime('%Y', market_date) AS year -- modifier for year is %Y
,strftime('%m', market_date) AS month -- modifier for month is %m
from customer_purchases
LIMIT 25;

--END QUERY

Expand All @@ -153,7 +204,12 @@ but remember, STRFTIME returns a STRING for your WHERE statement...
AND be sure you remove the LIMIT from the previous query before aggregating!! */
--QUERY 12



SELECT customer_id
,strftime('%Y', market_date) AS year -- modifier for year is %Y
,strftime('%m', market_date) AS month -- modifier for month is %m
,SUM(quantity* cost_to_customer_per_qty) as total_spend -- AGGREGATE FUNCTION
FROM customer_purchases
WHERE month = '04' AND year=='2022'
GROUP BY customer_id;

--END QUERY