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Empty file added pythonbridge/utils/__init__.py
Empty file.
13 changes: 13 additions & 0 deletions pythonbridge/utils/url.py
Original file line number Diff line number Diff line change
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def parse_url(url):

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🔵 [LOW] Style: The module lacks docstrings and type hints, which hurts readability and static analysis. Add a module docstring and annotate all functions, e.g., def parse_url(url: str) -> tuple[str, str] | None:.

parts = url.split("://")

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🟠 [HIGH] Bug / Robustness: Splitting the URL with url.split('://') is fragile – it fails for URLs that contain :// in the path, user‑info, or query string, and it does not validate the scheme. Prefer using the standard library: from urllib.parse import urlparse and return result.scheme, result.netloc + result.path.

Suggested fix:

from urllib.parse import urlparse

def parse_url(url: str) -> tuple[str, str] | None:
    try:
        parsed = urlparse(url)
        if not parsed.scheme or not parsed.netloc:
            return None
        return parsed.scheme, parsed.netloc + parsed.path
    except Exception:
        return None

if len(parts) != 2:

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🟠 [HIGH] Bug: parse_url can return None here but its callers are not checked. Add a check to handle None return values.

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🟡 [MEDIUM] ValueError: parse_url returns None for URLs with no protocol or more than one '://' (e.g. 'example.com', 'http://example.com//path'). Consider raising a ValueError with a descriptive message instead of returning None.

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🟠 [HIGH] Bug: parse_url returns None for URLs without a scheme (e.g. //example.com), but does not handle cases where the URL has multiple schemes (e.g. http://https://example.com). Consider raising a ValueError instead of returning None.

return None

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🟡 [MEDIUM] TypeError: parse_url returns None for invalid URLs but the caller might not check for it, leading to a TypeError when trying to access the returned value as a tuple. Consider raising a ValueError instead of returning None.

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🟡 [MEDIUM] Style / Error handling: Returning None on a malformed URL forces callers to remember to check the result. Raising a clear exception (e.g., ValueError) makes the contract explicit and prevents silent failures.

Suggested fix: Replace return None with raise ValueError('Invalid URL format').

return parts[0], parts[1]


def is_secure(url):

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🟡 [MEDIUM] Bug / Security: is_secure only checks the exact prefix "https://". It will return False for URLs with leading whitespace or mixed‑case scheme (e.g., " HTTPS://example.com"). Normalize the input before checking.

Suggested fix:

def is_secure(url: str) -> bool:
    return url.strip().lower().startswith('https://')

return url.startswith("https://")

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🔵 [LOW] Style: The security check only considers 'https' as secure. Consider supporting other secure protocols like 'sftp' or 'ssh' as well.

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🔵 [LOW] Insecurity: is_secure only checks if the URL starts with 'https://', but does not account for other secure protocols like 'sftp://'. Consider using a more comprehensive check, such as url.startswith(('https://', 'sftp://')).



def get_path(url):

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🔴 [CRITICAL] Bug / Crash risk: get_path accesses index [3] after url.split('/', 3). If the URL does not contain a path component (e.g., "http://example.com"), the split list is shorter than four elements, raising an IndexError and crashing the program.

Suggested fix: Use urllib.parse.urlparse to safely extract the path, or guard against short splits.

from urllib.parse import urlparse

def get_path(url: str) -> str:
    parsed = urlparse(url)
    return parsed.path.lstrip('/')

return url.split("/", 3)[3]

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🟡 [MEDIUM] Bug: get_path does not handle the case when the URL does not contain a path. Add error checking for this scenario.

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🟠 [HIGH] IndexError: get_path raises IndexError when the URL has fewer than 4 path segments (e.g. 'https://example.com', 'https://example.com/path'). Use url.split('/', 3) and check the length of the result before indexing.

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🟠 [HIGH] IndexError: get_path raises an IndexError when the URL has less than 4 path segments (e.g. https://example.com). Use url.split('/', 3) and check the length of the result before indexing it, or use a try-except block to catch the IndexError.

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🟡 [MEDIUM] IndexError: get_path raises IndexError when the URL has no path segment (e.g. https://example.com). Use url.split('/', 3)[3] if len(url.split('/', 3)) > 3 else ''.

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