⚡ Bolt: 벡터 최솟값 탐색 O(N)으로 최적화 - #291
Conversation
|
👋 Jules, reporting for duty! I'm here to lend a hand with this pull request. When you start a review, I'll add a 👀 emoji to each comment to let you know I've read it. I'll focus on feedback directed at me and will do my best to stay out of conversations between you and other bots or reviewers to keep the noise down. I'll push a commit with your requested changes shortly after. Please note there might be a delay between these steps, but rest assured I'm on the job! For more direct control, you can switch me to Reactive Mode. When this mode is on, I will only act on comments where you specifically mention me with New to Jules? Learn more at jules.google/docs. For security, I will only act on instructions from the user who triggered this task. |
|
Warning Review limit reachedNext included review available in 39 minutes. View limit detailsLimit details: You’ve used the included review currently available. You've used all free OSS reviews for now. Wait for the free limit to reset to keep reviewing this public repository. Review configuration: ⚙️ Run configurationConfiguration used: Organization UI Review profile: CHILL Plan: Pro Plus Run ID: 📒 Files selected for processing (2)
Thanks for using CodeRabbit! It's free for OSS, and your support helps us grow. If you like it, consider giving us a shout-out. Comment |
| if (any(!is.na(p_values))) { | ||
| p_values[is.na(p_values)] <- 1 | ||
| candidate <- names(sort(p_values, decreasing = FALSE))[1L] | ||
| candidate <- names(p_values)[which.min(p_values)] |
There was a problem hiding this comment.
📝 Info: which.min refactor preserves behavior
The swap from names(sort(p_values, decreasing = FALSE))[1L] to names(p_values)[which.min(p_values)] is equivalent. NAs are set to 1 first (surveyFA.R), names come from unique rownames (surveyFA.R), and both pick the first-occurring minimum on ties.
Was this helpful? React with 👍 or 👎 to provide feedback.
💡 What:
surveyFA함수에서 벡터의 최솟값을 찾을 때 불필요한sort()함수 사용을 O(N) 선형 시간 복잡도를 가지는which.min()으로 변경했습니다.🎯 Why:
sort(x)[1]을 사용하면 O(N log N)의 정렬 오버헤드가 발생하지만 최솟값을 찾기 위해 전체 배열을 정렬할 필요는 없습니다.📊 Impact: 요소가 많아질 때 정렬 연산을 피하여 메모리 및 시간 효율성을 개선했습니다.
🔬 Measurement: 모든 관련 test suite를 돌려 기존 기능이 정상 동작함을 확인했습니다.
PR created automatically by Jules for task 13555628161088141039 started by @seonghobae