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Copy path752.open-the-lock.java
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/*
* @lc app=leetcode id=752 lang=java
*
* [752] Open the Lock
*
* https://leetcode.com/problems/open-the-lock/description/
*
* algorithms
* Medium (46.99%)
* Total Accepted: 39.8K
* Total Submissions: 80.8K
* Testcase Example: '["0201","0101","0102","1212","2002"]\n"0202"'
*
*
* You have a lock in front of you with 4 circular wheels. Each wheel has 10
* slots: '0', '1', '2', '3', '4', '5', '6', '7', '8', '9'. The wheels can
* rotate freely and wrap around: for example we can turn '9' to be '0', or '0'
* to be '9'. Each move consists of turning one wheel one slot.
*
* The lock initially starts at '0000', a string representing the state of the
* 4 wheels.
*
* You are given a list of deadends dead ends, meaning if the lock displays any
* of these codes, the wheels of the lock will stop turning and you will be
* unable to open it.
*
* Given a target representing the value of the wheels that will unlock the
* lock, return the minimum total number of turns required to open the lock, or
* -1 if it is impossible.
*
*
* Example 1:
*
* Input: deadends = ["0201","0101","0102","1212","2002"], target = "0202"
* Output: 6
* Explanation:
* A sequence of valid moves would be "0000" -> "1000" -> "1100" -> "1200" ->
* "1201" -> "1202" -> "0202".
* Note that a sequence like "0000" -> "0001" -> "0002" -> "0102" -> "0202"
* would be invalid,
* because the wheels of the lock become stuck after the display becomes the
* dead end "0102".
*
*
*
* Example 2:
*
* Input: deadends = ["8888"], target = "0009"
* Output: 1
* Explanation:
* We can turn the last wheel in reverse to move from "0000" -> "0009".
*
*
*
* Example 3:
*
* Input: deadends = ["8887","8889","8878","8898","8788","8988","7888","9888"],
* target = "8888"
* Output: -1
* Explanation:
* We can't reach the target without getting stuck.
*
*
*
* Example 4:
*
* Input: deadends = ["0000"], target = "8888"
* Output: -1
*
*
*
* Note:
*
* The length of deadends will be in the range [1, 500].
* target will not be in the list deadends.
* Every string in deadends and the string target will be a string of 4 digits
* from the 10,000 possibilities '0000' to '9999'.
*
*
*/
class Solution {
/** One direction BSF
public int openLock(String[] deadends, String target) {
Queue<String> queue = new LinkedList<>();
Set<String> deadendSet = new HashSet<>(Arrays.asList(deadends));
queue.offer("0000");
int level = 0;
while (!queue.isEmpty()) {
int size = queue.size();
while (size > 0) {
size--;
String lock = queue.poll();
if (deadendSet.contains(lock)) {
continue;
}
if (target.equals(lock)) {
return level;
}
deadendSet.add(lock);
StringBuilder sb = new StringBuilder(lock);
for (int i = 0; i < 4; i++) {
char c = sb.charAt(i);
String l1 = sb.substring(0, i) + (c == '0' ? 9 : c - '0' - 1) + sb.substring(i + 1);
String l2 = sb.substring(0, i) + (c == '9' ? 0 : c - '0' + 1) + sb.substring(i + 1);
if (!deadendSet.contains(l1)) {
queue.offer(l1);
}
if (!deadendSet.contains(l2)) {
queue.offer(l2);
}
}
}
level++;
}
return -1;
}
*/
// Two end BSF
public int openLock(String[] deadends, String target) {
Set<String> begin = new HashSet<>();
Set<String> end = new HashSet<>();
begin.add("0000");
end.add(target);
Set<String> deadendSet = new HashSet<>(Arrays.asList(deadends));
int level = 0;
while (!begin.isEmpty() && !end.isEmpty()) {
Set<String> tmp = new HashSet<>();
for (String lock : begin) {
if (deadendSet.contains(lock)) {
continue;
}
if (end.contains(lock)) {
return level;
}
deadendSet.add(lock);
StringBuilder sb = new StringBuilder(lock);
for (int i = 0; i < 4; i++) {
char c = sb.charAt(i);
String l1 = sb.substring(0, i) + (c == '0' ? 9 : c - '0' - 1) + sb.substring(i + 1);
String l2 = sb.substring(0, i) + (c == '9' ? 0 : c - '0' + 1) + sb.substring(i + 1);
if (!deadendSet.contains(l1)) {
tmp.add(l1);
}
if (!deadendSet.contains(l2)) {
tmp.add(l2);
}
}
}
begin = end;
end = tmp;
level++;
}
return -1;
}
}