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Copy path75.sort-colors.java
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67 lines (64 loc) · 1.67 KB
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/*
* @lc app=leetcode id=75 lang=java
*
* [75] Sort Colors
*
* https://leetcode.com/problems/sort-colors/description/
*
* algorithms
* Medium (42.30%)
* Total Accepted: 330.5K
* Total Submissions: 776.7K
* Testcase Example: '[2,0,2,1,1,0]'
*
* Given an array with n objects colored red, white or blue, sort them in-place
* so that objects of the same color are adjacent, with the colors in the order
* red, white and blue.
*
* Here, we will use the integers 0, 1, and 2 to represent the color red,
* white, and blue respectively.
*
* Note: You are not suppose to use the library's sort function for this
* problem.
*
* Example:
*
*
* Input: [2,0,2,1,1,0]
* Output: [0,0,1,1,2,2]
*
* Follow up:
*
*
* A rather straight forward solution is a two-pass algorithm using counting
* sort.
* First, iterate the array counting number of 0's, 1's, and 2's, then
* overwrite array with total number of 0's, then 1's and followed by 2's.
* Could you come up with a one-pass algorithm using only constant space?
*
*
*/
class Solution {
public void sortColors(int[] nums) {
if (nums == null || nums.length == 0) {
return;
}
int redIndex = 0;
int blueIndex = nums.length - 1;
int cur = 0;
while (cur <= blueIndex) {
if (nums[cur] == 0) {
swap(nums, cur++, redIndex++);
} else if (nums[cur] == 2) {
swap(nums, cur, blueIndex--);
} else {
cur++;
}
}
}
private void swap(int[] nums, int i, int j) {
int tmp = nums[i];
nums[i] = nums[j];
nums[j] = tmp;
}
}