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Copy path674.longest-continuous-increasing-subsequence.java
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66 lines (62 loc) · 1.37 KB
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/*
* @lc app=leetcode id=674 lang=java
*
* [674] Longest Continuous Increasing Subsequence
*
* https://leetcode.com/problems/longest-continuous-increasing-subsequence/description/
*
* algorithms
* Easy (44.66%)
* Total Accepted: 85.6K
* Total Submissions: 189.7K
* Testcase Example: '[1,3,5,4,7]'
*
*
* Given an unsorted array of integers, find the length of longest continuous
* increasing subsequence (subarray).
*
*
* Example 1:
*
* Input: [1,3,5,4,7]
* Output: 3
* Explanation: The longest continuous increasing subsequence is [1,3,5], its
* length is 3.
* Even though [1,3,5,7] is also an increasing subsequence, it's not a
* continuous one where 5 and 7 are separated by 4.
*
*
*
* Example 2:
*
* Input: [2,2,2,2,2]
* Output: 1
* Explanation: The longest continuous increasing subsequence is [2], its
* length is 1.
*
*
*
* Note:
* Length of the array will not exceed 10,000.
*
*/
class Solution {
public int findLengthOfLCIS(int[] nums) {
if (nums.length == 0) {
return 0;
}
int max = 1;
int cur = 1;
for (int i = 1; i < nums.length; i++) {
if (nums[i] > nums[i - 1]) {
cur++;
} else {
cur = 1;
}
if (cur > max) {
max = cur;
}
}
return max;
}
}