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Copy path20.valid-parentheses.java
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82 lines (79 loc) · 1.47 KB
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/*
* @lc app=leetcode id=20 lang=java
*
* [20] Valid Parentheses
*
* https://leetcode.com/problems/valid-parentheses/description/
*
* algorithms
* Easy (37.02%)
* Total Accepted: 874.7K
* Total Submissions: 2.3M
* Testcase Example: '"()"'
*
* Given a string containing just the characters '(', ')', '{', '}', '[' and
* ']', determine if the input string is valid.
*
* An input string is valid if:
*
*
* Open brackets must be closed by the same type of brackets.
* Open brackets must be closed in the correct order.
*
*
* Note that an empty string is also considered valid.
*
* Example 1:
*
*
* Input: "()"
* Output: true
*
*
* Example 2:
*
*
* Input: "()[]{}"
* Output: true
*
*
* Example 3:
*
*
* Input: "(]"
* Output: false
*
*
* Example 4:
*
*
* Input: "([)]"
* Output: false
*
*
* Example 5:
*
*
* Input: "{[]}"
* Output: true
*
*
*/
class Solution {
public boolean isValid(String s) {
Stack<Character> stack = new Stack<>();
for (char c : s.toCharArray()) {
if (c == '{' || c == '[' || c == '(') {
stack.push(c);
} else {
if (stack.isEmpty() || !inPair(stack.pop(), c)) {
return false;
}
}
}
return stack.isEmpty();
}
private boolean inPair(char c1, char c2) {
return (c1 == '{' && c2 == '}') || (c1 == '[' && c2 == ']') || (c1 == '(' && c2 == ')');
}
}