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Copy pathOptimalGameStrategy1(DP).cpp
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106 lines (88 loc) · 3.22 KB
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#include "algorithm"
#include "iostream"
#include "numeric"
#include "iomanip"
#include "cstring"
#include "math.h"
#include "bitset"
#include "string"
#include "vector"
#include "ctime"
#include "queue"
#include "stack"
#include "map"
#include "set"
#include "ext/pb_ds/assoc_container.hpp" // Common file
#include "ext/pb_ds/tree_policy.hpp" // Including tree_order_statistics_node_update
#include "ext/pb_ds/detail/standard_policies.hpp"
using namespace std;
using namespace __gnu_pbds;
#define f first
#define lgn 25
#define endl '\n'
#define sc second
#define pb push_back
#define N (int)2e3+5
#define PI acos(-1.0)
#define int long long
#define vi vector<int>
#define mod 1000000007
#define ld long double
#define eb emplace_back
#define mii map<int,int>
#define vpii vector<pii>
#define pii pair<int,int>
#define pq priority_queue
#define BLOCK (int)sqrt(N)
#define test(x) while(x--)
#define all(x) begin(x),end(x)
#define allr(x) rbegin(x),rend(x)
#define fo(i,a,n) for(int i=a;i<n;i++)
#define rfo(i,n,a) for(int i=n;i>=a;i--)
#define FAST ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define time() cerr << "Time : " << (double)clock() / (double)CLOCKS_PER_SEC << "s\n"
#define bug(...) __f (#__VA_ARGS__, __VA_ARGS__)
typedef tree< int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update >
OS ;
template <typename Arg1>
void __f (const char* name, Arg1&& arg1) { cout << name << " : " << arg1 << endl; }
template <typename Arg1, typename... Args>
void __f (const char* names, Arg1&& arg1, Args&&... args)
{
const char* comma = strchr (names + 1, ',');
cout.write (names, comma - names) << " : " << arg1 << " | "; __f (comma + 1, args...);
}
const int inf = 0x3f3f3f3f;
const int INF = 0x3f3f3f3f3f3f3f3f;
int n,m,k,q;
string s;
int a[N] , dp[N][N]; // dp[i][j] -> maximum score we can achieved in range from i to j
void go()
{
cin >> n;
fo(i,1,n+1) cin >> a[i];
fo(i,1,n+1) dp[i][i] = a[i]; // len = 1
fo(i,1,n) dp[i][i+1] = max( a[i] , a[i+1] ); // len = 2
for( int gap = 2; gap <= n; gap++)
{
for( int i = 1; i + gap <= n; i++)
{
int j = i + gap;
int xx = a[i] + min( { dp[i+2][j] , dp[i+1][j-1] }); // if we take ith element the next range for opponent will be (i+1,j) ,
// as he is also play optimally so he will also choose maximum he can get
// in that range so , let it takes i+1 element then we have option of (i+2,j)
// and if he take jth element then we have option of (i+1,j-1) so we will take the
// minimum of both ranges because maximum is taken by opponent because he was also playing optimally
int yy = a[j] + min( { dp[i][j-2] , dp[i+1][j-1] });
dp[i][j] = max( xx , yy );
}
}
cout << dp[1][n] << endl;
}
int32_t main()
{
FAST;
int t=1;
// cin>>t;
test(t) go();
}