-
Notifications
You must be signed in to change notification settings - Fork 3
Expand file tree
/
Copy pathBaliPairs(DP).cpp
More file actions
119 lines (100 loc) · 3.67 KB
/
Copy pathBaliPairs(DP).cpp
File metadata and controls
119 lines (100 loc) · 3.67 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
#include "algorithm"
#include "iostream"
#include "numeric"
#include "iomanip"
#include "cstring"
#include "math.h"
#include "bitset"
#include "string"
#include "vector"
#include "ctime"
#include "queue"
#include "stack"
#include "map"
#include "set"
#include "ext/pb_ds/assoc_container.hpp" // Common file
#include "ext/pb_ds/tree_policy.hpp" // Including tree_order_statistics_node_update
#include "ext/pb_ds/detail/standard_policies.hpp"
using namespace std;
using namespace __gnu_pbds;
#define f first
#define lgn 25
#define endl '\n'
#define sc second
#define pb push_back
#define N (int)2e5+5
#define PI acos(-1.0)
#define int long long
#define vi vector<int>
#define mod 1000000007
#define ld long double
#define eb emplace_back
#define mii map<int,int>
#define vpii vector<pii>
#define pii pair<int,int>
#define pq priority_queue
#define BLOCK (int)sqrt(N)
#define test(x) while(x--)
#define all(x) begin(x),end(x)
#define allr(x) rbegin(x),rend(x)
#define fo(i,a,n) for(int i=a;i<n;i++)
#define rfo(i,n,a) for(int i=n;i>=a;i--)
#define FAST ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define time() cerr << "Time : " << (double)clock() / (double)CLOCKS_PER_SEC << "s\n"
#define bug(...) __f (#__VA_ARGS__, __VA_ARGS__)
typedef tree< int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update >
OS ;
template <typename Arg1>
void __f (const char* name, Arg1&& arg1) { cout << name << " : " << arg1 << endl; }
template <typename Arg1, typename... Args>
void __f (const char* names, Arg1&& arg1, Args&&... args)
{
const char* comma = strchr (names + 1, ',');
cout.write (names, comma - names) << " : " << arg1 << " | "; __f (comma + 1, args...);
}
const int inf = 0x3f3f3f3f;
const int INF = 0x3f3f3f3f3f3f3f3f;
int n,m,k,q;
string s;
vi adj[N];
pii a[N];
int dp[N][2]; // 1 -> ways to make odd sum till ith index
// 0 -> ways to make even sum till ith index
void go()
{
cin >> n;
int ans = 0;
memset( dp , 0 , sizeof dp );
dp[0][1] = 0; // base case for odd sum
dp[0][0] = 1; // base case for even sum
fo(i,1,n+1)
{
int x , y;
cin >> x >> y;
x &= 1;
y &= 1;
if( x and y ) // both odd
{
dp[i][1] = ( dp[i-1][0] * 2 )%mod; // to make odd sum we need total ways to make even sum since ( odd + even -> odd) and we have 2 odd here
dp[i][0] = ( dp[i-1][1] * 2 )%mod; // // to make even sum we need total ways to make odd sum since ( odd + odd -> even) and we have 2 odd here
}
else if( !x and !y ) // both even
{
dp[i][1] = ( dp[i-1][1] * 2 )%mod; // to make odd sum we need total ways to make odd sum since ( odd + even -> odd) and we have 2 even here
dp[i][0] = ( dp[i-1][0] * 2 )%mod; // to make even sum we need total ways to make even sum since ( even + even -> even) and we have 2 even here
}
else // one odd and one even
{
dp[i][1] = ( dp[i-1][0] + dp[i-1][1] )%mod; // to have odd sum now we can make it by taking previous ways to make odd sum and now 1 even and vice versa.
dp[i][0] = ( dp[i-1][1] + dp[i-1][0] )%mod; // to have even sum now we can make it by taking previous ways to make even sum and now 1 even and vice versa.
}
}
cout << dp[n][1]%mod << endl; // print number of ways to make odd sum
}
int32_t main()
{
FAST;
int t=1;
cin>>t;
test(t) go();
}