|
| 1 | +// -------------------- Problem -------------------- |
| 2 | +/* |
| 3 | +Rudolf looks at snowflakes and imagines building one using a graph. |
| 4 | +
|
| 5 | +Start with a single vertex. |
| 6 | +Connect it to k new vertices (k must be greater than 1). |
| 7 | +After that, every vertex that has only one connection grows k more vertices. |
| 8 | +This growing step must happen at least once. |
| 9 | +
|
| 10 | +Given a number n, we need to check whether it’s possible to end up |
| 11 | +with exactly n vertices using some value of k. |
| 12 | +*/ |
| 13 | + |
| 14 | +// -------------------- What’s actually going on -------------------- |
| 15 | +/* |
| 16 | +After each growth step, the total number of vertices becomes: |
| 17 | +
|
| 18 | +1 + k + k^2 + k^3 + ... + k^d |
| 19 | +
|
| 20 | +So the problem is just checking whether n can be written like this |
| 21 | +for some k >= 2 and d >= 2. |
| 22 | +*/ |
| 23 | + |
| 24 | +// -------------------- Main idea -------------------- |
| 25 | +/* |
| 26 | +Trying every k directly is too slow, especially in Java. |
| 27 | +
|
| 28 | +But the number of growth layers (d) is small. |
| 29 | +Even with k = 2, values blow past 10^18 after about 60 layers. |
| 30 | +
|
| 31 | +So we loop over all possible depths d (from 2 to ~60), |
| 32 | +and for each depth we binary search the value of k. |
| 33 | +*/ |
| 34 | + |
| 35 | +// -------------------- How the checking works -------------------- |
| 36 | +/* |
| 37 | +For a fixed d: |
| 38 | +- Pick a k using binary search |
| 39 | +- Compute 1 + k + k^2 + ... + k^d carefully |
| 40 | +- Stop early if the value becomes too big or overflows |
| 41 | +
|
| 42 | +If we ever hit exactly n, we print YES. |
| 43 | +Otherwise, after all tries, we print NO. |
| 44 | +*/ |
| 45 | + |
| 46 | +// -------------------- Complexity -------------------- |
| 47 | +/* |
| 48 | +For each test case: |
| 49 | +- We try at most 60 values of d |
| 50 | +- For each d, we do a binary search on k |
| 51 | +
|
| 52 | +Time complexity: O(60 * log n) |
| 53 | +Space complexity: O(1) |
| 54 | +*/ |
| 55 | + |
| 56 | +// -------------------- Submission -------------------- |
| 57 | +/* |
| 58 | +https://codeforces.com/contest/1846/submission/356040210 |
| 59 | +*/ |
| 60 | + |
| 61 | +// -------------------- Code ------------------------- |
| 62 | + |
| 63 | +import java.io.BufferedReader; |
| 64 | +import java.io.InputStreamReader; |
| 65 | + |
| 66 | +public class Solution2 { |
| 67 | + |
| 68 | + static final long LIMIT = (long) 1e18; |
| 69 | + |
| 70 | + public static void main(String[] args) throws Exception { |
| 71 | + BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); |
| 72 | + int t = Integer.parseInt(br.readLine().trim()); |
| 73 | + |
| 74 | + StringBuilder out = new StringBuilder(); |
| 75 | + |
| 76 | + while (t-- > 0) { |
| 77 | + long n = Long.parseLong(br.readLine().trim()); |
| 78 | + out.append(canMakeSnowflake(n) ? "YES\n" : "NO\n"); |
| 79 | + } |
| 80 | + |
| 81 | + System.out.print(out.toString()); |
| 82 | + } |
| 83 | + |
| 84 | + static boolean canMakeSnowflake(long n) { |
| 85 | + for (int d = 2; d <= 60; d++) { |
| 86 | + long left = 2; |
| 87 | + long right = (long) Math.pow(n, 1.0 / d) + 1; |
| 88 | + |
| 89 | + while (left <= right) { |
| 90 | + long mid = (left + right) >>> 1; |
| 91 | + long value = calcSum(mid, d); |
| 92 | + |
| 93 | + if (value == n) return true; |
| 94 | + if (value < 0 || value > n) right = mid - 1; |
| 95 | + else left = mid + 1; |
| 96 | + } |
| 97 | + } |
| 98 | + return false; |
| 99 | + } |
| 100 | + |
| 101 | + static long calcSum(long k, int d) { |
| 102 | + long sum = 1; |
| 103 | + long cur = 1; |
| 104 | + |
| 105 | + for (int i = 1; i <= d; i++) { |
| 106 | + if (cur > LIMIT / k) return -1; |
| 107 | + cur *= k; |
| 108 | + if (sum > LIMIT - cur) return -1; |
| 109 | + sum += cur; |
| 110 | + } |
| 111 | + |
| 112 | + return sum; |
| 113 | + } |
| 114 | +} |
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