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| 1 | +#include<bits/stdc++.h> |
| 2 | +#include<queue> |
| 3 | +using namespace std; |
| 4 | +typedef unordered_map<int, int> umii; |
| 5 | +typedef unordered_map<long long, long long> umll; |
| 6 | +typedef unordered_map<char, long long> umci; |
| 7 | +typedef vector<pair<int, int>> vpi; |
| 8 | +typedef vector<int> vi; |
| 9 | +typedef long long ll; |
| 10 | +typedef vector<long long> vll; |
| 11 | +typedef unordered_map<int , bool> umib; |
| 12 | +#define sum(v) accumulate(v.begin(), v.end(), 0) |
| 13 | +#define endl '\n' |
| 14 | +#define f0(i, n) for(long long i = 0; i < n; i++) |
| 15 | +#define f1(i, n) for(long long i = 1; i < n; i++) |
| 16 | +#define as(v) sort(v.begin(), v.end()) |
| 17 | +#define all(x) (x).begin(), (x).end() |
| 18 | +#define pb push_back |
| 19 | +template<class T> umll frequency(vector<T> &v) {umll freq;for(auto &x:v) freq[x]++; return freq;} |
| 20 | +template<class T> umci S_frequency(vector<T> &v) {umci freq;for(auto &x:v) freq[x]++; return freq;} |
| 21 | +template <class T> void input(vector<T> &v){for(auto &x:v)cin>>x;} |
| 22 | +ll power(ll x, ll y){ ll res = 1; while (y > 0){ if (y & 1) res = (ll)(res*x); y = y>>1; x = (ll)(x*x); } return res; } |
| 23 | +void pvll(const vector<long long> &arr){for(auto it : arr){cout << it << " ";}cout << endl;} |
| 24 | +void pvi(const vector<int> &arr){for(auto it : arr){cout << it << " ";}cout << endl;} |
| 25 | + |
| 26 | + |
| 27 | +void solve(){ |
| 28 | + |
| 29 | +//-------------INPUT------------- |
| 30 | + ll n; |
| 31 | + cin >> n; |
| 32 | + vll v(n); |
| 33 | + input(v); |
| 34 | + sort(all(v)); |
| 35 | + map<ll,ll>mp; |
| 36 | + ll req = abs(v[n-1]-v[0]); |
| 37 | + ll ans=0; |
| 38 | + for(ll i=0;i<n;i++) |
| 39 | + { |
| 40 | + ll target = (v[i]-req); |
| 41 | + if(mp.find(target)!=mp.end()) |
| 42 | + { |
| 43 | + // cout << v[i] << " " << target << " "; |
| 44 | + ans+= (mp[target]); |
| 45 | + } |
| 46 | + mp[v[i]]++; |
| 47 | + } |
| 48 | + cout << 2*ans << endl; |
| 49 | + |
| 50 | + // explanation :- this is basic 2 sum type question where map stores the frequency of previous elements |
| 51 | + // time complexity is o(nlogn) |
| 52 | + |
| 53 | + // submission link:- https://codeforces.com/contest/1771/submission/355275950 |
| 54 | + |
| 55 | + |
| 56 | +//-------------CODE-------------- |
| 57 | + |
| 58 | + |
| 59 | + |
| 60 | +} |
| 61 | + |
| 62 | + |
| 63 | +int main(){ |
| 64 | + int tt; cin >> tt; while(tt--) |
| 65 | +{solve();}; |
| 66 | +} |
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