Add solution for circle problem in Solution1.cpp

Implement solution for finding person in circle based on given conditions.

Author: Abh-igyan

Problems/Mathematics/Day-01/sol/Abhigyan/Solution1.cpp

@@ -0,0 +1,42 @@
+/* 1 to n people are standing in a circle. n is even.... a is looking at b. 
+If given c is looking at some d person for given a,b then find that d. If such a combination
+of circle does not exist then print -1*/
+
+// Time complexity: O(1)
+// Space complexity: O(1)
+//My submission: https://codeforces.com/contest/1560/submission/355204246
+
+#include <bits/stdc++.h>
+using namespace std;
+
+using ll = long long;
+#define all(x) (x).begin(), (x).end()
+
+const int MOD = 1e9 + 7; // 998244353
+const ll INF = 1e18;
+
+void solve() {
+    int a,b,c;
+    cin>>a>>b>>c;
+    int n=2*abs(a-b);
+    if(a>n || b>n ||c>n ) cout<<-1<<endl;
+    else{
+        int x=c-n/2,y=c+n/2;
+        if(x>=1 && x<=n) cout<<x<<endl;
+        else cout<<y<<endl;
+    }
+}
+
+int main() {
+    // Fast I/O
+    ios::sync_with_stdio(false);
+    cin.tie(nullptr);
+
+    int t;
+    cin >> t;
+    while (t--) {
+        solve();
+    }
+    
+    return 0;
+}