Merge pull request #371 from ViMo018/patch-5

Add solution for parentheses scoring problem

Author: Dheeraj-06

Problems/Data-structures/Day-04/sol/Vishva Modh/soln1.cpp

@@ -0,0 +1,101 @@
+#include<bits/stdc++.h>
+#include<queue>
+using namespace std;
+typedef unordered_map<int, int> umii;
+typedef unordered_map<long long, long long> umll;
+typedef unordered_map<char, long long> umci;
+typedef vector<pair<int, int>> vpi;
+typedef vector<int> vi;
+typedef long long ll;
+typedef vector<long long> vll;
+typedef unordered_map<int , bool> umib;
+#define sum(v) accumulate(v.begin(), v.end(), 0)
+#define endl '\n'
+#define f0(i, n) for(long long i = 0; i < n; i++)
+#define f1(i, n) for(long long i = 1; i < n; i++)
+#define as(v) sort(v.begin(), v.end())
+#define all(x) (x).begin(), (x).end()
+#define pb push_back
+template<class T> umll frequency(vector<T> &v) {umll freq;for(auto &x:v) freq[x]++; return freq;}
+template<class T> umci S_frequency(vector<T> &v) {umci freq;for(auto &x:v) freq[x]++; return freq;}
+template <class T> void input(vector<T> &v){for(auto &x:v)cin>>x;}
+ll power(ll x, ll y){ ll res = 1; while (y > 0){ if (y & 1) res = (ll)(res*x); y = y>>1; x = (ll)(x*x); } return res; }
+void pvll(const vector<long long> &arr){for(auto it : arr){cout << it << " ";}cout << endl;}
+void pvi(const vector<int> &arr){for(auto it : arr){cout << it << " ";}cout << endl;}
+
+//function to check score i will use stack data structure
+//time complexity = o(n);
+
+//submission link :- https://codeforces.com/contest/1997/submission/355833501
+
+
+ll checkscore(string s)
+{
+    ll ans=0;
+    stack<ll>st;
+
+    for(ll i=0;i<s.size();i++)
+    {
+        if(s[i] == '(')
+        {
+            st.push(i);
+        }
+        else{
+            ll a = st.top();
+            ans+= i-a;
+            st.pop();
+        }
+    }
+    return ans;
+}
+
+void solve(){
+
+//-------------INPUT-------------
+    ll n; 
+    cin >> n;
+    // make an rbs first
+    // approach whenever open>0 do it close to make minimum score
+
+    string s;
+    cin >> s;
+
+
+//-------------CODE--------------
+
+    ll open=0;
+    ll close=0;
+
+    for(ll i=0;i<n;i++)
+    {
+        if(s[i] == '(')
+        {
+            open++;
+        }
+        else if(s[i] == ')')
+        {
+            open--;
+        }
+        else if(s[i] == '_' && open==0)
+        {
+            s[i] = '(';
+            open++;
+        }
+        else if(s[i] == '_' && open>0)
+        {
+            s[i] = ')';
+            open--;
+        }
+    }
+
+    cout << checkscore(s) << endl;
+    
+
+
+}
+
+
+int main(){
+    int tt; cin >> tt; while(tt--)
+{solve();};
+}