Merge pull request #147 from DeadlySatwik/issue3

Issue3

Author: zonedoutdg

Problems/Mathematics/Day-01/sol/Satwik_Santosh/.cph/.Solution1.cpp_c67c6042fed1bb34ccbfc5368abbf7ee.prob

@@ -0,0 +1 @@
+{"name":"Local: Solution1","url":"c:\\Project\\OpenCode25\\CP-Chronicles\\Problems\\Mathematics\\Day-01\\sol\\Satwik_Santosh\\Solution1.cpp","tests":[{"id":1766771594036,"input":"","output":""}],"interactive":false,"memoryLimit":1024,"timeLimit":3000,"srcPath":"c:\\Project\\OpenCode25\\CP-Chronicles\\Problems\\Mathematics\\Day-01\\sol\\Satwik_Santosh\\Solution1.cpp","group":"local","local":true}

Problems/Mathematics/Day-01/sol/Satwik_Santosh/Solution1.cpp

@@ -0,0 +1,71 @@
+/*
+Problem Statement:
+There are n people standing in a circle (n is even). Each person looks at the person
+standing exactly opposite them. Given that person a looks at person b, determine
+the person that person c is looking at.
+
+---------------------------------------
+Approach:
+1. Determine the circle size (n): Since 'a' and 'b' are opposite, the distance between them 
+is half the circle. Thus, n = 2 * |a - b|.
+2. Validation: If any of the given numbers (a, b, c) aregreater than n, the configuration 
+is impossible. Output -1.
+3. Find opposite of 'c': The person opposite to 'c' is at a distance of n/2 from 'c'.
+
+----------------------------------------
+
+Time Complexity: O(1)
+
+Space Complexity: O(1)
+
+----------------------------------------
+Example:
+Input:
+a = 1, b = 3, c = 2
+
+Process : 
+1. Calculate diff = |1 - 3| = 2
+2. Calculate n = 2 * diff = 4  
+3. Since c = 2, calculate opposite:
+   - c + diff = 2 + 2 = 4 (which is <= n)
+   - So, the person opposite to c is 4.
+
+Output:
+4
+*/
+
+#include <bits/stdc++.h>
+using namespace std;
+#define ll long long
+#define out(x) cout << (x) << endl
+#define outr(x)          \
+    {                    \
+        cout << x << endl; \
+        return;          \
+    }
+
+void solve()
+{
+    ll a, b, c;
+    cin >> a >> b >> c;
+    ll diff = abs(a - b);
+    ll n = diff * 2;
+
+    if (a > n || b > n || c > n)
+    {
+        outr(-1);
+    }
+    ll ans = c + diff;
+    if (ans > n)
+        ans -= n;
+    out(ans);
+}
+
+int main()
+{
+    ll t;
+    cin >> t;
+    while (t--)
+        solve();
+    return 0;
+}

Problems/Mathematics/Day-01/sol/Saurav_Gitte/Solution1.cpp

@@ -68,4 +68,6 @@ int main() {
         cout << ans << "\n";
     }
     return 0;
-}
+}
+
+//Submission Link: https://codeforces.com/problemset/submission/1560/355215212