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| 1 | +#include<bits/stdc++.h> |
| 2 | +#include<queue> |
| 3 | +using namespace std; |
| 4 | +typedef unordered_map<int, int> umii; |
| 5 | +typedef unordered_map<long long, long long> umll; |
| 6 | +typedef unordered_map<char, long long> umci; |
| 7 | +typedef vector<pair<int, int>> vpi; |
| 8 | +typedef vector<int> vi; |
| 9 | +typedef long long ll; |
| 10 | +typedef vector<long long> vll; |
| 11 | +typedef unordered_map<int , bool> umib; |
| 12 | +#define sum(v) accumulate(v.begin(), v.end(), 0) |
| 13 | +#define endl '\n' |
| 14 | +#define f0(i, n) for(long long i = 0; i < n; i++) |
| 15 | +#define f1(i, n) for(long long i = 1; i < n; i++) |
| 16 | +#define as(v) sort(v.begin(), v.end()) |
| 17 | +#define all(x) (x).begin(), (x).end() |
| 18 | +#define pb push_back |
| 19 | +template<class T> umll frequency(vector<T> &v) {umll freq;for(auto &x:v) freq[x]++; return freq;} |
| 20 | +template<class T> umci S_frequency(vector<T> &v) {umci freq;for(auto &x:v) freq[x]++; return freq;} |
| 21 | +template <class T> void input(vector<T> &v){for(auto &x:v)cin>>x;} |
| 22 | +ll power(ll x, ll y){ ll res = 1; while (y > 0){ if (y & 1) res = (ll)(res*x); y = y>>1; x = (ll)(x*x); } return res; } |
| 23 | +void pvll(const vector<long long> &arr){for(auto it : arr){cout << it << " ";}cout << endl;} |
| 24 | +void pvi(const vector<int> &arr){for(auto it : arr){cout << it << " ";}cout << endl;} |
| 25 | + |
| 26 | +const int N=7; |
| 27 | +ll ans =0; |
| 28 | +vector<vector<ll>> vis(N, vector<ll>(N, 0)); |
| 29 | +string s; |
| 30 | + |
| 31 | +bool inside(ll i,ll j) |
| 32 | +{ |
| 33 | + // this is to check whether our pointer is in bounded area or not |
| 34 | + return i>=0 && i<N && j>=0 && j<N; |
| 35 | +} |
| 36 | + |
| 37 | +void dfs(ll x,ll y,ll step) |
| 38 | +{ |
| 39 | + // Base Condition |
| 40 | + |
| 41 | + if(step == N*N-1 || (x== N-1 && y==0)) |
| 42 | + { |
| 43 | + // if i reached bottom left with 48 steps |
| 44 | + if(step == N*N-1 && (x== N-1 && y==0)) |
| 45 | + { |
| 46 | + |
| 47 | + ans+=1; |
| 48 | + } |
| 49 | + return; |
| 50 | + } |
| 51 | + |
| 52 | + // Trapped Optimisation |
| 53 | + |
| 54 | + // above and below are visited(or out of bounds) and left and righ is free |
| 55 | + |
| 56 | + if((!inside(x-1,y) || vis[x-1][y]) && (!inside(x+1,y) || vis[x+1][y])) |
| 57 | + { |
| 58 | + if(inside(x,y-1) && !vis[x][y-1] && inside(x,y+1) && !vis[x][y+1]) |
| 59 | + { |
| 60 | + return; |
| 61 | + // TRAPPED |
| 62 | + } |
| 63 | + } |
| 64 | + |
| 65 | + // left and right are visited/out of bound and up and down are free |
| 66 | + |
| 67 | + if((!inside(x,y-1) || vis[x][y-1]) && (!inside(x,y+1) || vis[x][y+1])) |
| 68 | + { |
| 69 | + if(inside(x-1,y) && !vis[x-1][y] && inside(x+1,y) && !vis[x+1][y]) |
| 70 | + { |
| 71 | + return; |
| 72 | + //TRAPPED |
| 73 | + } |
| 74 | + } |
| 75 | + |
| 76 | + // mark the visited cell as one so we dont visit again |
| 77 | + |
| 78 | + vis[x][y] =1; |
| 79 | + |
| 80 | + if(s[step]=='?' || s[step] == 'L') |
| 81 | + { |
| 82 | + if(inside(x,y-1) && !vis[x][y-1]) |
| 83 | + { |
| 84 | + dfs(x,y-1,step+1); |
| 85 | + } |
| 86 | + } |
| 87 | + if(s[step] == '?' || s[step] == 'R') |
| 88 | + { |
| 89 | + if(inside(x,y+1) && !vis[x][y+1]) |
| 90 | + { |
| 91 | + dfs(x,y+1,step+1); |
| 92 | + } |
| 93 | + } |
| 94 | + if(s[step] == '?' || s[step] == 'U') |
| 95 | + { |
| 96 | + if(inside(x-1,y) && !vis[x-1][y]) |
| 97 | + { |
| 98 | + dfs(x-1,y,step+1); |
| 99 | + } |
| 100 | + } |
| 101 | + if(s[step] == '?' || s[step] == 'D') |
| 102 | + { |
| 103 | + if(inside(x+1,y) && !vis[x+1][y]) |
| 104 | + { |
| 105 | + dfs(x+1,y,step+1); |
| 106 | + } |
| 107 | + } |
| 108 | + |
| 109 | + //backtracking after exploring one route now i will go back and will do vis[x][y] = 0; |
| 110 | + |
| 111 | + vis[x][y]=0; |
| 112 | + |
| 113 | + |
| 114 | + |
| 115 | +} |
| 116 | + |
| 117 | +// SUBMISSION LINK:- https://cses.fi/problemset/result/15756456/ |
| 118 | + |
| 119 | + |
| 120 | + |
| 121 | +void solve(){ |
| 122 | + cin >> s; |
| 123 | + |
| 124 | + dfs(0,0,0); |
| 125 | + cout << ans << endl; |
| 126 | + |
| 127 | + // TimeComplexity :- O(48*88414) == O(48*1e5) |
| 128 | + |
| 129 | + //SpaceComplexity = O(49) |
| 130 | + |
| 131 | +//-------------INPUT------------- |
| 132 | + |
| 133 | + |
| 134 | + |
| 135 | +//-------------CODE-------------- |
| 136 | + |
| 137 | + |
| 138 | + |
| 139 | +} |
| 140 | + |
| 141 | + |
| 142 | +int main(){ |
| 143 | + //int tt; cin >> tt; while(tt--) |
| 144 | +{solve();}; |
| 145 | +} |
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