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Day-01/sol/Aditi_Deshmukh
Day-02/sol/Aditi_Deshmukh Expand file tree Collapse file tree Original file line number Diff line number Diff line change 1+ // We need to find what numbered person is oppisite to the person numbered 'c'
2+ // On the basis of 'a' and 'b' being opposites
3+ // Time and space complexity are both O(1)
4+
5+
6+ #include < bits/stdc++.h>
7+ using namespace std ;
8+
9+ int main () {
10+ int t;
11+ cin>>t;
12+ while (t--){
13+ int a,b,c;
14+ cin>>a>>b>>c;
15+ // eg: 1,4,5
16+
17+ int n=abs (a-b)*2 ;
18+ // n=6
19+
20+ if (c>n){
21+ // 5>6 is false
22+ // c>n then c would be out of the possible numbers
23+ cout<<" -1" <<endl;
24+ continue ;
25+ }
26+
27+ if (c>(n/2 )){
28+ // 5>3 implies the number opposite to it is in the lower half
29+ cout<<c-(n/2 )<<endl;
30+ }
31+ else {
32+ cout<<c+(n/2 )<<endl;
33+ }
34+
35+ }
36+
37+
Original file line number Diff line number Diff line change 1+ // We have to find how many pairs have the maximum absolute difference
2+ // only the highest and the lowest number in the array will have max difference
3+ // so we need to find how many times the highest and lwest element appears and calc their permutations
4+ // time and space complexity is O(n)
5+ #include < bits/stdc++.h>
6+ using namespace std ;
7+
8+ int main () {
9+ int t;
10+ cin>>t;
11+ while (t--){
12+ long long int n;
13+ cin>>n;
14+ int a[n];
15+ for (int i=0 ;i<n;i++){
16+ cin>>a[i];
17+ }
18+ long long int j=1 ,k=1 ,min=a[0 ],max=a[0 ];
19+ // j is no of min elements
20+ // k is no of max elements
21+
22+ for (int i=1 ;i<n;i++){
23+ if (min<a[i]){
24+ j=1 ;
25+ min=a[i];
26+ }
27+ else if (min==a[i]){
28+ j++;
29+ }
30+
31+ if (max>a[i]){
32+ k=1 ;
33+ max=a[i];
34+ }
35+ else if (max==a[i]){
36+ k++;
37+ }
38+ }
39+
40+ if (min==max)
41+ // if all elements are same, permutation formula becomes n*(n-1)
42+ cout<<n*(n-1 )<<endl;
43+ else
44+ cout<<j*k*2 <<endl;
45+ }
46+
47+ }
48+ // https://codeforces.com/problemset/submission/1771/355657715
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