|
| 1 | +/* |
| 2 | +Problem Summary: |
| 3 | +- Given a partially known regular bracket sequence. |
| 4 | +- Odd positions are missing ('_'), even positions are fixed. |
| 5 | +- Restore missing brackets to form a valid RBS with minimum total cost. |
| 6 | +- Cost = sum of distances between matched bracket pairs. |
| 7 | +
|
| 8 | +Key Ideas: |
| 9 | +- Valid RBS requires balance never goes negative. |
| 10 | +- To minimize cost, close brackets as early as possible. |
| 11 | +- Only open a bracket when forced. |
| 12 | +
|
| 13 | +Greedy Strategy: |
| 14 | +- Traverse left to right. |
| 15 | +- Maintain current balance and a stack of '(' positions. |
| 16 | +- At '_' positions: |
| 17 | + • If balance == 0 → must place '(' |
| 18 | + • Else → place ')' |
| 19 | +- At fixed positions: |
| 20 | + • Follow given '(' or ')' |
| 21 | +
|
| 22 | +Cost Calculation: |
| 23 | +- On encountering ')', pop matching '(' from stack. |
| 24 | +- Add (currentIndex - openIndex) to total cost. |
| 25 | +
|
| 26 | +Complexity: |
| 27 | +- Time: O(n) per test case |
| 28 | +- Space: O(n) |
| 29 | +
|
| 30 | +Problem submission link:---------------------------------------------------------------------------------- |
| 31 | +https://codeforces.com/contest/1997/submission/355801157 |
| 32 | +*/ |
| 33 | + |
| 34 | +import java.io.*; |
| 35 | +import java.util.*; |
| 36 | + |
| 37 | +public class Solution1 { |
| 38 | + public static void main(String[] args) throws Exception { |
| 39 | + FastScanner fs = new FastScanner(System.in); |
| 40 | + StringBuilder out = new StringBuilder(); |
| 41 | + |
| 42 | + int t = fs.nextInt(); |
| 43 | + while (t-- > 0) { |
| 44 | + int n = fs.nextInt(); |
| 45 | + char[] s = fs.next().toCharArray(); |
| 46 | + |
| 47 | + int balance = 0; |
| 48 | + long cost = 0; |
| 49 | + Deque<Integer> stack = new ArrayDeque<>(); |
| 50 | + |
| 51 | + for (int i = 0; i < n; i++) { |
| 52 | + if ((i & 1) == 0) { |
| 53 | + if (balance == 0) { |
| 54 | + stack.push(i); |
| 55 | + balance++; |
| 56 | + } else { |
| 57 | + balance--; |
| 58 | + int openPos = stack.pop(); |
| 59 | + cost += i - openPos; |
| 60 | + } |
| 61 | + } else { |
| 62 | + if (s[i] == '(') { |
| 63 | + stack.push(i); |
| 64 | + balance++; |
| 65 | + } else { |
| 66 | + balance--; |
| 67 | + int openPos = stack.pop(); |
| 68 | + cost += i - openPos; |
| 69 | + } |
| 70 | + } |
| 71 | + } |
| 72 | + |
| 73 | + out.append(cost).append('\n'); |
| 74 | + } |
| 75 | + |
| 76 | + System.out.print(out); |
| 77 | + } |
| 78 | + |
| 79 | + static class FastScanner { |
| 80 | + private final byte[] buffer = new byte[1 << 16]; |
| 81 | + private int ptr = 0, len = 0; |
| 82 | + private final InputStream in; |
| 83 | + |
| 84 | + FastScanner(InputStream in) { |
| 85 | + this.in = in; |
| 86 | + } |
| 87 | + |
| 88 | + private int read() throws IOException { |
| 89 | + if (ptr >= len) { |
| 90 | + len = in.read(buffer); |
| 91 | + ptr = 0; |
| 92 | + if (len <= 0) return -1; |
| 93 | + } |
| 94 | + return buffer[ptr++]; |
| 95 | + } |
| 96 | + |
| 97 | + int nextInt() throws IOException { |
| 98 | + int c; |
| 99 | + do { |
| 100 | + c = read(); |
| 101 | + } while (c <= ' '); |
| 102 | + boolean neg = false; |
| 103 | + if (c == '-') { |
| 104 | + neg = true; |
| 105 | + c = read(); |
| 106 | + } |
| 107 | + int val = 0; |
| 108 | + while (c > ' ') { |
| 109 | + val = val * 10 + (c - '0'); |
| 110 | + c = read(); |
| 111 | + } |
| 112 | + return neg ? -val : val; |
| 113 | + } |
| 114 | + |
| 115 | + String next() throws IOException { |
| 116 | + int c; |
| 117 | + do { |
| 118 | + c = read(); |
| 119 | + } while (c <= ' '); |
| 120 | + StringBuilder sb = new StringBuilder(); |
| 121 | + while (c > ' ') { |
| 122 | + sb.append((char) c); |
| 123 | + c = read(); |
| 124 | + } |
| 125 | + return sb.toString(); |
| 126 | + } |
| 127 | + } |
| 128 | +} |
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