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test: 两个键会在同一个包里相遇,而没有任何判据覆盖这件事
## e2e 304:提供层的包同时带私有目录
`openkal-musl` 就是这个形状 —— `provides = ["mcpp:c-abi=musl"]` **加上**内部头
覆盖层。层的目录到达**每一个**单元,所以在这里误发布覆盖层比在别处都宽:musl 的
`hidden`/`weak` 宏不只落到它的消费者,而是落到整个构建的每一个翻译单元。
两者按构造是相容的(目标侧取的是提供者的 `publicUsage`,而那已经是过滤后的集合)
—— 「按构造」正是需要一条断言的地方。反向对照实测:把 fixture 里的
`private_include_dirs` 拿掉,判据当场检出
/tmp/.../dep/src/sibling.cppm ← 兄弟依赖包
/tmp/.../src/main.cpp ← 根
也就是把那句「爆炸半径」从注释变成了读数。⭐ 另加控制:提供者自己的单元必须仍然
带着它,否则「没泄漏」和「整个丢掉了」同读数。
## e2e 305:glob 在展开之后比对
文档承诺「条目支持 `*` glob 并在展开之后比对」,而没有判据。加 `gen/*` 两条边:
提供者两个目录都要有,消费者一个都不能有。⭐ 判据落到 `gen/one`/`gen/two` **按名**
而不是 `gen`—— 只查 `gen` 的话,一个拿未展开拼写去比的实现照样通过。
反向对照实测:把 glob 从 private 列表里拿掉,两条都变红并各自点名。1 parent ff24a88 commit 32fc574
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