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hashing.cpp
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82 lines (62 loc) · 1.9 KB
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#include <bits/stdc++.h>
using namespace std;
/*
Build: O(n)
Substring hash: O(1)
Check palindrome: O(1)
*/
#define ll long long
#define hash apdmfoiwahofqjenfoj
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
ll rnd(ll a, ll b){return uniform_int_distribution<ll>(a, b)(rng);}
const ll mod = 1e9+7;
ll modpow(ll x, ll n){
if (n == 0) return 1;
ll y = modpow(x, n/2);
if (n&1) return y*y % mod * x % mod;
return y*y % mod;
}
struct hash{
int n;
vector<ll>prefix, suffix;
vector<ll>power, inverse;
hash(const string &s, ll p){
n = (int)s.size();
power.assign(n, 0);
inverse.assign(n, 0);
p %= mod;
ll ip = modpow(p, mod-2); // inverse of p
power[0] = inverse[0] = 1;
for(int i = 1;i < n;i++) power[i] = power[i-1]*p % mod;
for(int i = 1;i < n;i++) inverse[i] = inverse[i-1]*ip % mod;
prefix.assign(n, 0);
suffix.assign(n, 0);
prefix[0] = s[0];
suffix[n-1] = s[n-1];
for(int i = 1;i < n;i++) prefix[i] = (prefix[i-1] + s[i]*power[i] % mod) % mod;
for(int i = n-2;i >= 0;i--) suffix[i] = (suffix[i+1] + s[i]*power[n-1-i] % mod) % mod;
}
ll substr(int i, int j){
if (i == 0) return prefix[j];
return (prefix[j]-prefix[i-1]+mod) % mod *inverse[i] % mod;
}
ll rsubstr(int i, int j){
if (j == n-1) return suffix[i];
return (suffix[i]-suffix[j+1]+mod) % mod *inverse[n-1-j] % mod;
}
bool is_palindrome(int i, int j){
if (i == j) return true;
int len = j-i+1;
int k = len/2;
return substr(i, i+k-1) == rsubstr(j-k+1, j);
}
};
int main(){
string s = "abacaba";
int n = (int)s.size();
hash h(s, rnd(100, mod-2));
cout << h.substr(0, n-1) << endl;
cout << h.rsubstr(0, n-1) << endl;
cout << h.is_palindrome(0, n-1) << endl;
return 0;
}