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/*
Given an integer array nums and an integer k, return the number of non-empty subarrays that have a sum divisible by k.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [4,5,0,-2,-3,1], k = 5
Output: 7
Explanation: There are 7 subarrays with a sum divisible by k = 5:
[4, 5, 0, -2, -3, 1], [5], [5, 0], [5, 0, -2, -3], [0], [0, -2, -3], [-2, -3]
Example 2:
Input: nums = [5], k = 9
Output: 0
Constraints:
1 <= nums.length <= 3 * 104
-104 <= nums[i] <= 104
2 <= k <= 104
*/
import java.util.*;
class Subarray_Sums_Divisible_by_K {
public int subarraysDivByK(int[] nums, int k) {
int n = nums.length ;
int prefix = 0;
int count =0 ;
HashMap <Integer,Integer> map = new HashMap <>();
map.put(0,1);
for(int i = 0; i<n ; i++){
prefix = prefix + nums[i];
int need = prefix %k ;
if(need <0){
need = need + k ;
}
if(map.containsKey(need)){
count = count + map.get(need);
}
map.put(need , map.getOrDefault(need,0)+1);
}
return count ;
}
}