[pre-commit.ci] auto fixes from pre-commit.com hooks

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Author: pre-commit-ci[bot]

dynamic_programming/longest_palindromic_substring.py

@@ -1,6 +1,7 @@
 # reference :https://www.geeksforgeeks.org/dsa/longest-palindromic-substring/
 
-def longest_palindromic_substring(s:str)->str:
+
+def longest_palindromic_substring(s: str) -> str:
     """
     This function returns longest palindromic substring in a string using DP
     s : input string
@@ -15,34 +16,35 @@ def longest_palindromic_substring(s:str)->str:
     >>> longest_palindromic_substring("")
     ''
     """
-    n=len(s)
+    n = len(s)
 
-    dp=[[False for i in range(n)] for j in range(n)]
-    start=0
-    max_length=1
+    dp = [[False for i in range(n)] for j in range(n)]
+    start = 0
+    max_length = 1
 
     for i in range(n):
-        dp[i][i]=True
-    
+        dp[i][i] = True
+
     # for length 2 palindrome check
-    for i in range(n-1):
-        if s[i]==s[i+1]:
-            dp[i][i+1]=True
-            start=i
-            max_length=2
+    for i in range(n - 1):
+        if s[i] == s[i + 1]:
+            dp[i][i + 1] = True
+            start = i
+            max_length = 2
 
     # for length 3 and above
-    for length in range(3,n+1):
-        for i in range(n-length+1):
-            j=i+length-1
-            if s[i]==s[j] and dp[i+1][j-1]:
-                dp[i][j]=True
-                start=i
-                max_length=length
+    for length in range(3, n + 1):
+        for i in range(n - length + 1):
+            j = i + length - 1
+            if s[i] == s[j] and dp[i + 1][j - 1]:
+                dp[i][j] = True
+                start = i
+                max_length = length
 
-    return s[start:start+max_length]
+    return s[start : start + max_length]
 
-def manacher_algorithm(s:str)->str:
+
+def manacher_algorithm(s: str) -> str:
     """
     This function returns the longest palindromic substring in a string using Manacher's algorithm
     >>> longest_palindromic_substring("babad")
@@ -56,27 +58,28 @@ def manacher_algorithm(s:str)->str:
     >>> longest_palindromic_substring("")
     ''
     """
-    T='^#'+'#'.join(s)+'#$'
-    n=len(T)
+    T = "^#" + "#".join(s) + "#$"
+    n = len(T)
+
+    p = [0] * n
+    c = 0
+    r = 0
 
-    p=[0]*n
-    c=0
-    r=0
+    for i in range(1, n - 1):
+        mirror = 2 * c - i
+        if i < r:
+            p[i] = min(r - i, p[mirror])
+        while T[i + (1 + p[i])] == T[i - (1 + p[i])]:
+            p[i] += 1
+        if i + p[i] > r:
+            c = i
+            r = i + p[i]
 
-    for i in range(1,n-1):
-        mirror=2*c-i
-        if i<r:
-            p[i]=min(r-i,p[mirror])
-        while T[i+(1+p[i])]==T[i-(1+p[i])]:
-            p[i]+=1
-        if i+p[i]>r:
-            c=i
-            r=i+p[i]
+    max_length = max(p)
+    max_center = p.index(max_length)
+    start = (max_center - max_length) // 2
+    return s[start : start + max_length]
 
-    max_length=max(p)
-    max_center=p.index(max_length)
-    start=(max_center-max_length)//2
-    return s[start:start+max_length]
 
 if __name__ == "__main__":
     import doctest