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Fix: Broadened type hints for geometric_progression to allow float inputs and added doctest
1 parent a71618f commit 26b49d5

2 files changed

Lines changed: 15 additions & 5 deletions

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conversions/length_conversion.py

Lines changed: 3 additions & 2 deletions
Original file line numberDiff line numberDiff line change
@@ -30,13 +30,14 @@ class FromTo(NamedTuple):
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to_factor: float
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# The 'inche' key is removed as the code already handles the plural 's' via rstrip("s").
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TYPE_CONVERSION = {
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"millimeter": "mm",
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"centimeter": "cm",
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"meter": "m",
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"kilometer": "km",
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"inch": "in",
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"inche": "in", # Trailing 's' has been stripped off
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# "inche": "in", # Removed redundant/misspelled key
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"feet": "ft",
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"foot": "ft",
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"yard": "yd",
@@ -99,7 +100,7 @@ def length_conversion(value: float, from_type: str, to_type: str) -> float:
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0.1181103
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>>> length_conversion(4, "wrongUnit", "inch")
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Traceback (most recent call last):
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...
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...
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ValueError: Invalid 'from_type' value: 'wrongUnit'.
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Conversion abbreviations are: mm, cm, m, km, in, ft, yd, mi
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"""

maths/sum_of_geometric_progression.py

Lines changed: 12 additions & 3 deletions
Original file line numberDiff line numberDiff line change
@@ -1,7 +1,11 @@
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from typing import Union
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# ... other imports ...
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def sum_of_geometric_progression(
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first_term: int, common_ratio: int, num_of_terms: int
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# FIX: Changed 'int' to 'Union[int, float]' to allow non-integer terms/ratios
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first_term: Union[int, float], common_ratio: Union[int, float], num_of_terms: int
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) -> float:
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""" "
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"""
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Return the sum of n terms in a geometric progression.
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>>> sum_of_geometric_progression(1, 2, 10)
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1023.0
@@ -19,10 +23,15 @@ def sum_of_geometric_progression(
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-341.0
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>>> sum_of_geometric_progression(1, 2, -10)
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-0.9990234375
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# NEW DOCTEST to validate float inputs
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>>> sum_of_geometric_progression(0.5, 2, 3)
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3.5
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"""
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if common_ratio == 1:
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# Formula for sum if common ratio is 1
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return num_of_terms * first_term
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# Formula for finding sum of n terms of a GeometricProgression
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return (first_term / (1 - common_ratio)) * (1 - common_ratio**num_of_terms)
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# Note: Python's standard float arithmetic handles this correctly for the fix.
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return (first_term / (1 - common_ratio)) * (1 - common_ratio**num_of_terms)

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