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| 1 | +import java.io.BufferedReader; |
| 2 | +import java.io.IOException; |
| 3 | +import java.io.InputStreamReader; |
| 4 | +import java.util.Arrays; |
| 5 | + |
| 6 | +/* |
| 7 | + * Problem: |
| 8 | + * Given an array of integers of size `n`. Now 2 players are playing a game with this array. |
| 9 | + * They make their turn alternatively and in each turn, they pick a number from either end and add it to their score. |
| 10 | + * If player 1 gets more or equal score than the player 2, player 1 wins otherwise player 2 wins. |
| 11 | + * Both players play the game optimally. |
| 12 | + * |
| 13 | + * Approach: Dynamic Programming |
| 14 | + * As we know both players play optimally, |
| 15 | + * If a player pick an element from either end then next player will also try to maximize the score and will try to minimize other player's score |
| 16 | + * So for subarray `i` and `j`, the recurrence would be, |
| 17 | + * dp[i][j] = Math.max( |
| 18 | + * a[i] + Math.min(dp[i + 1][j - 1], dp[i + 2][j]), |
| 19 | + * a[j] + Math.min(dp[i + 1][j - 1], dp[i][j - 2]) |
| 20 | + * ) |
| 21 | + * and base case would be dp[i][i] = a[i] |
| 22 | + * Complexity: |
| 23 | + * Time complexity = O(n * n) // as we have 2 dp states, the complexity is squared |
| 24 | + * Space complexity = O(n * n) // as we are calculating an answer for each subarray, the complexity is also squared |
| 25 | + */ |
| 26 | + |
| 27 | +public class PredictTheWinner { |
| 28 | + private static boolean PredictTheWinner(int[] nums) { |
| 29 | + int totalScore = 0; |
| 30 | + for(int i = 0; i < nums.length; i++) { |
| 31 | + totalScore += nums[i]; |
| 32 | + } |
| 33 | + |
| 34 | + int[][] dp = new int[nums.length][nums.length]; |
| 35 | + for(int i = 0; i < nums.length; i++) { |
| 36 | + for(int j = 0; j < nums.length; j++ ) { |
| 37 | + dp[i][j] = -1; |
| 38 | + } |
| 39 | + } |
| 40 | + |
| 41 | + int player1Score = score(nums, 0, nums.length - 1, dp); |
| 42 | + int player2Score = totalScore - player1Score; |
| 43 | + return player1Score >= player2Score; |
| 44 | + } |
| 45 | + |
| 46 | + private static int score(int[] nums, int i, int j, int[][] dp) { |
| 47 | + if(i > j) return 0; |
| 48 | + if(i == j) return nums[i]; |
| 49 | + |
| 50 | + if(dp[i][j] != -1) return dp[i][j]; |
| 51 | + |
| 52 | + int selectLeft = nums[i] + Math.min( |
| 53 | + score(nums, i + 2, j, dp), |
| 54 | + score(nums, i + 1, j - 1, dp) |
| 55 | + ); |
| 56 | + |
| 57 | + int selectRight = nums[j] + Math.min( |
| 58 | + score(nums, i, j - 2, dp), |
| 59 | + score(nums, i + 1, j - 1, dp) |
| 60 | + ); |
| 61 | + |
| 62 | + return dp[i][j] = Math.max(selectLeft, selectRight); |
| 63 | + } |
| 64 | + |
| 65 | + public static void main(String[] args) throws IOException { |
| 66 | + BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); |
| 67 | + int n = Integer.parseInt(br.readLine()); |
| 68 | + |
| 69 | + int[] array = Arrays.stream(br.readLine().split(" ")).mapToInt(Integer::parseInt).toArray(); |
| 70 | + |
| 71 | + System.out.println(PredictTheWinner(array)); |
| 72 | + } |
| 73 | +} |
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