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Add <p> tags to all feedback
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‎pretext/ClassesBasics/UserDefinedClasses.ptx‎

Lines changed: 8 additions & 8 deletions
Original file line numberDiff line numberDiff line change
@@ -166,33 +166,33 @@ print(x, y)
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<statement>
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<p>True True</p>
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</statement>
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<feedback>
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<feedback><p>
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Look closely at how the objects are instantiated.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>True False</p>
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</statement>
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<feedback>
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<feedback><p>
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Look closely at how the objects are instantiated and the types of the objects.
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</feedback>
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</p></feedback>
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</choice>
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<choice correct="yes">
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<statement>
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<p>False True</p>
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</statement>
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<feedback>
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<feedback><p>
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Correct, the BMW object is not the Tesla object but they are of the same type.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>False False</p>
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</statement>
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<feedback>
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<feedback><p>
194194
Look closer at types of the objects.
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>

‎pretext/Debugging/HowtoAvoidDebugging.ptx‎

Lines changed: 6 additions & 6 deletions
Original file line numberDiff line numberDiff line change
@@ -75,25 +75,25 @@ print(final_time)
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<statement>
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<p>Python is stupid and does not know how to add properly.</p>
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</statement>
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<feedback>
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<feedback><p>
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No, Python is probabaly not broken.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>There is nothing wrong here.</p>
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</statement>
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<feedback>
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<feedback><p>
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No, try adding the two numbers together yourself, you will definitely get a different result.
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</feedback>
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</p></feedback>
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</choice>
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<choice correct="yes">
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<statement>
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<p>Python is doing string concatenation, not integer addition.</p>
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</statement>
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<feedback>
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<feedback><p>
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Yes! Remember that input returns a string. Now we will need to convert the string to an integer
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>

‎pretext/Debugging/KnowyourerrorMessages.ptx‎

Lines changed: 6 additions & 6 deletions
Original file line numberDiff line numberDiff line change
@@ -44,25 +44,25 @@ print(final_time_int)
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<statement>
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<p>You cannot use a variable on both the left and right hand sides of an assignment statement.</p>
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</statement>
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<feedback>
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<feedback><p>
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No, You can, as long as all the variables on the right hand side already have values.
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</feedback>
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</p></feedback>
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</choice>
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<choice correct="yes">
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<statement>
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<p>wait_time_int does not have a value so it cannot be used on the right hand side.</p>
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</statement>
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<feedback>
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<feedback><p>
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Yes. Variables must already have values in order to be used on the right hand side.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>This is not really an error, Python is broken.</p>
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</statement>
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<feedback>
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<feedback><p>
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No, No, No!
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>

‎pretext/Dictionaries/Aliasingandcopying.ptx‎

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Original file line numberDiff line numberDiff line change
@@ -45,33 +45,33 @@ print(mydict["elephant"])
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<statement>
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<p>23</p>
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</statement>
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<feedback>
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<feedback><p>
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mydict and yourdict are both names for the same dictionary.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>None</p>
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</statement>
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<feedback>
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<feedback><p>
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The dictionary is mutable so changes can be made to the keys and values.
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</feedback>
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</p></feedback>
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</choice>
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<choice correct="yes">
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<statement>
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<p>999</p>
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</statement>
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<feedback>
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<feedback><p>
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Yes, since yourdict is an alias for mydict, the value for the key elephant has been changed.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>Error, there are two different keys named elephant.</p>
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</statement>
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<feedback>
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<feedback><p>
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There is only one dictionary with only one key named elephant. The dictionary has two different names, mydict and yourdict.
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>

‎pretext/Dictionaries/Dictionarymethods.ptx‎

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Original file line numberDiff line numberDiff line change
@@ -179,33 +179,33 @@ print(keylist[3])
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<statement>
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<p>cat</p>
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</statement>
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<feedback>
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<feedback><p>
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keylist is a list of all the keys which is then sorted. cat would be at index 1.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>dog</p>
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</statement>
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<feedback>
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<feedback><p>
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keylist is a list of all the keys which is then sorted. dog would be at index 2.
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</feedback>
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</p></feedback>
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</choice>
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<choice correct="yes">
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<statement>
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<p>elephant</p>
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</statement>
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<feedback>
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<feedback><p>
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Yes, the list of keys is sorted and the item at index 3 is printed.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>bear</p>
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</statement>
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<feedback>
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<feedback><p>
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keylist is a list of all the keys which is then sorted. bear would be at index 0.
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>
@@ -225,33 +225,33 @@ print(answer)
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<statement>
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<p>2</p>
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</statement>
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<feedback>
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<feedback><p>
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get returns the value associated with a given key so this divides 12 by 6.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>0.5</p>
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</statement>
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<feedback>
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<feedback><p>
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12 is divided by 6, not the other way around.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>bear</p>
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</statement>
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<feedback>
244+
<feedback><p>
245245
Take another look at the example for get above. get returns the value associated with a given key.
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</feedback>
246+
</p></feedback>
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</choice>
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<choice>
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<statement>
250250
<p>Error, divide is not a valid operation on dictionaries.</p>
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</statement>
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<feedback>
252+
<feedback><p>
253253
The integer division operator is being used on the values returned from the get method, not on the dictionary.
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>
@@ -270,17 +270,17 @@ print("dog" in mydict)
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<statement>
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<p>True</p>
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</statement>
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<feedback>
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<feedback><p>
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Yes, dog is a key in the dictionary.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>False</p>
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</statement>
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<feedback>
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<feedback><p>
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The in operator returns True if a key is in the dictionary, False otherwise.
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>
@@ -299,17 +299,17 @@ print(23 in mydict)
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<statement>
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<p>True</p>
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</statement>
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<feedback>
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<feedback><p>
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23 is a value in the dictionary, not a key.
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</feedback>
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</p></feedback>
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</choice>
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<choice correct="yes">
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<statement>
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<p>False</p>
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</statement>
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<feedback>
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<feedback><p>
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Yes, the in operator returns True if a key is in the dictionary, False otherwise.
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</feedback>
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</p></feedback>
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</choice>
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</choices>
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</exercise>
@@ -332,33 +332,33 @@ print(total)
332332
<statement>
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<p>18</p>
334334
</statement>
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<feedback>
335+
<feedback><p>
336336
Add the values that have keys greater than 3, not equal to 3.
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</feedback>
337+
</p></feedback>
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</choice>
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<choice correct="yes">
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<statement>
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<p>43</p>
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</statement>
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<feedback>
343+
<feedback><p>
344344
Yes, the for statement iterates over the keys. It adds the values of the keys that have length greater than 3.
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</feedback>
345+
</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>0</p>
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</statement>
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<feedback>
351+
<feedback><p>
352352
This is the accumulator pattern. total starts at 0 but then changes as the iteration proceeds.
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</feedback>
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</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>61</p>
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</statement>
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<feedback>
359+
<feedback><p>
360360
Not all the values are added together. The if statement only chooses some of them.
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</feedback>
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</p></feedback>
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</choice>
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</choices>
364364
</exercise>

‎pretext/Dictionaries/Dictionaryoperations.ptx‎

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Original file line numberDiff line numberDiff line change
@@ -55,33 +55,33 @@ print(mydict["mouse"])
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<statement>
5656
<p>12</p>
5757
</statement>
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<feedback>
58+
<feedback><p>
5959
12 is associated with the key cat.
60-
</feedback>
60+
</p></feedback>
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</choice>
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<choice>
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<statement>
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<p>0</p>
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</statement>
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<feedback>
66+
<feedback><p>
6767
The key mouse will be associated with the sum of the two values.
68-
</feedback>
68+
</p></feedback>
6969
</choice>
7070
<choice correct="yes">
7171
<statement>
7272
<p>18</p>
7373
</statement>
74-
<feedback>
74+
<feedback><p>
7575
Yes, add the value for cat and the value for dog (12 + 6) and create a new entry for mouse.
76-
</feedback>
76+
</p></feedback>
7777
</choice>
7878
<choice>
7979
<statement>
8080
<p>Error, there is no entry with mouse as the key.</p>
8181
</statement>
82-
<feedback>
82+
<feedback><p>
8383
Since the new key is introduced on the left hand side of the assignment statement, a new key-value pair is added to the dictionary.
84-
</feedback>
84+
</p></feedback>
8585
</choice>
8686
</choices>
8787
</exercise>

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