It should state that it returns a dict as it it is computed per traces.
def path(df: pd.DataFrame = None, traces: dict[str, list[pd.DataFrame]] = None) -> pd.DataFrame:
"""
Calculate the path length for the given DataFrame.
This function computes the path length based on the Euclidean distance between consecutive points.
Parameters:
df (pd.DataFrame): DataFrame containing 'x' and 'y' columns.
traces (dict): A dictionary with keys as (sessionId) and values as lists of DataFrames. If None, traces will be computed from df.
Returns:
pd.DataFrame: DataFrame with an additional 'distance' column representing the path length.
"""
if traces is None:
validate_dataframe(df)
traces = extract_traces_by_session(df)
for session_id, session_traces in traces.items():
for i in range(len(session_traces)):
validate_dataframe(session_traces[i])
# Compute the distance for each trace
for j in range(len(session_traces)):
session_traces[j]['distance'] = _path(session_traces[j])['distance']
# Store the traces with distance in the dictionary
traces[session_id] = session_traces
return traces
It should state that it returns a dict as it it is computed per traces.