Complete Sprint-3 coursework

Author: AkliluMihtsun

Sprint-3/1-key-errors/0.js

@@ -1,22 +1,22 @@
-// Predict and explain first...
-//  I am predicting the code will generate error because the variable str is declared twice
-
-// call the function capitalise with a string input
-// interpret the error message and figure out why an error is occurring
-
-/*function capitalise(str) {
-  let str = `${str[0].toUpperCase()}${str.slice(1)}`;
-  return str;
-}
-console.log(capitalise("hello World"));*/
-
-// After we run the code, it generated this error SyntaxError: Identifier str has already been declared
-// This happened because we tried to declare again using the keyword let the variable str
-// which was declared before in the parameter of the function
-
-//Here is the fixed code
-function capitalise(str) {
-  str = `${str[0].toUpperCase()}${str.slice(1)}`;
-  return str;
-}
-console.log(capitalise("hello World"));
+// Predict and explain first...
+//  I am predicting the code will generate error because the variable str is declared twice
+
+// call the function capitalise with a string input
+// interpret the error message and figure out why an error is occurring
+
+/*function capitalise(str) {
+  let str = `${str[0].toUpperCase()}${str.slice(1)}`;
+  return str;
+}
+console.log(capitalise("hello World"));*/
+
+// After we run the code, it generated this error SyntaxError: Identifier str has already been declared
+// This happened because we tried to declare again using the keyword let the variable str
+// which was declared before in the parameter of the function
+
+//Here is the fixed code
+function capitalise(str) {
+  str = `${str[0].toUpperCase()}${str.slice(1)}`;
+  return str;
+}
+console.log(capitalise("hello World"));

Sprint-3/1-key-errors/1.js

@@ -1,32 +1,32 @@
-// Predict and explain first...
-
-// Why will an error occur when this program runs?
-// I predict the code will generate 2 errors because one the variable decimalNumber is declared twice and two
-// the function is not called instead the variable decimalNumber is called and it can't be accessed because
-// it was declared locally as a parameter of the function
-
-// Try playing computer with the example to work out what is going on
-
-/*function convertToPercentage(decimalNumber) {
-  const decimalNumber = 0.5;
-  const percentage = `${decimalNumber * 100}%`;
-
-  return percentage;
-}
-
-console.log(decimalNumber);*/
-
-// After we run the code, it generated an error SyntaxError: Identifier 'decimalNumber' has already been declared
-// because we tried to declare decimalNumber again. After fixing this error again we got another error ReferenceError: decimalNumber is not defined
-// because the decimalNumber is locally scoped, javascript can't access it when the function is called
-// additionally the function was not called  console.log(decimalNumber) this simply means print the value of decimalNumber
-
-// Finally, correct the code to fix the problem
-// Here is the fixed code
-function convertToPercentage(decimalNumber) {
-  const percentage = `${decimalNumber * 100}%`;
-
-  return percentage;
-}
-
-console.log(convertToPercentage(0.5));
+// Predict and explain first...
+
+// Why will an error occur when this program runs?
+// I predict the code will generate 2 errors because one the variable decimalNumber is declared twice and two
+// the function is not called instead the variable decimalNumber is called and it can't be accessed because
+// it was declared locally as a parameter of the function
+
+// Try playing computer with the example to work out what is going on
+
+/*function convertToPercentage(decimalNumber) {
+  const decimalNumber = 0.5;
+  const percentage = `${decimalNumber * 100}%`;
+
+  return percentage;
+}
+
+console.log(decimalNumber);*/
+
+// After we run the code, it generated an error SyntaxError: Identifier 'decimalNumber' has already been declared
+// because we tried to declare decimalNumber again. After fixing this error again we got another error ReferenceError: decimalNumber is not defined
+// because the decimalNumber is locally scoped, javascript can't access it when the function is called
+// additionally the function was not called  console.log(decimalNumber) this simply means print the value of decimalNumber
+
+// Finally, correct the code to fix the problem
+// Here is the fixed code
+function convertToPercentage(decimalNumber) {
+  const percentage = `${decimalNumber * 100}%`;
+
+  return percentage;
+}
+
+console.log(convertToPercentage(0.5));

Sprint-3/1-key-errors/2.js

@@ -1,21 +1,21 @@
-// Predict and explain first BEFORE you run any code...
-
-// this function should square any number but instead we're going to get an error
-
-// I predict the error will come from the argument because when we write a function we first declare parameters not values
-
-/*function square(3) {
-    return num * num;
-}*/
-
-// SyntaxError: Unexpected number
-
-// this error tells us javascript expects valid variable identifiers when function is defined not values
-
-// Finally, correct the code to fix the problem
-
-// Here is the fixed code
-function square(num) {
-  return num * num;
-}
-console.log(square(3));
+// Predict and explain first BEFORE you run any code...
+
+// this function should square any number but instead we're going to get an error
+
+// I predict the error will come from the argument because when we write a function we first declare parameters not values
+
+/*function square(3) {
+    return num * num;
+}*/
+
+// SyntaxError: Unexpected number
+
+// this error tells us javascript expects valid variable identifiers when function is defined not values
+
+// Finally, correct the code to fix the problem
+
+// Here is the fixed code
+function square(num) {
+  return num * num;
+}
+console.log(square(3));

Sprint-3/2-mandatory-debug/0.js

@@ -1,22 +1,22 @@
-// Predict and explain first...
-
-// I predict the code will run normally and print the result of a * b on the first console, but it will return undefined on the
-// second console.log
-
-/*function multiply(a, b) {
-  console.log(a * b);
-}
-
-console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);*/
-
-// The reason for printing undefined is that we didn't define a return value so the js doesn't know what to return and it simply returns undefined
-// We can fix the code by replacing the console.log with a return keyword so the js knows what to return when the function is called
-
-// Finally, correct the code to fix the problem
-// Here is the fixed code
-
-function multiply(a, b) {
-  return a * b;
-}
-
-console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);
+// Predict and explain first...
+
+// I predict the code will run normally and print the result of a * b on the first console, but it will return undefined on the
+// second console.log
+
+/*function multiply(a, b) {
+  console.log(a * b);
+}
+
+console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);*/
+
+// The reason for printing undefined is that we didn't define a return value so the js doesn't know what to return and it simply returns undefined
+// We can fix the code by replacing the console.log with a return keyword so the js knows what to return when the function is called
+
+// Finally, correct the code to fix the problem
+// Here is the fixed code
+
+function multiply(a, b) {
+  return a * b;
+}
+
+console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);

Sprint-3/2-mandatory-debug/1.js

@@ -1,21 +1,21 @@
-// Predict and explain first...
-//  I predict that the code will run but it will print undefined because the return expression is not setup properly
-
-/*function sum(a, b) {
-  return;
-  a + b;
-}
-
-console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);*/
-
-// When we run the code it printed out undefined because the return keyword is there but the expression that needs to be returned is not on the same line
-// therefore the return keyword can't reach the expression and the expression is ignored because the function has done execution right after it reaches the return keyword
-
-// Finally, correct the code to fix the problem
-// Here is the fixed code
-
-function sum(a, b) {
-  return a + b;
-}
-
-console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);
+// Predict and explain first...
+//  I predict that the code will run but it will print undefined because the return expression is not setup properly
+
+/*function sum(a, b) {
+  return;
+  a + b;
+}
+
+console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);*/
+
+// When we run the code it printed out undefined because the return keyword is there but the expression that needs to be returned is not on the same line
+// therefore the return keyword can't reach the expression and the expression is ignored because the function has done execution right after it reaches the return keyword
+
+// Finally, correct the code to fix the problem
+// Here is the fixed code
+
+function sum(a, b) {
+  return a + b;
+}
+
+console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);

Sprint-3/2-mandatory-debug/2.js

@@ -1,36 +1,36 @@
-// Predict and explain first...
-
-// Predict the output of the following code:
-// I predict the code will run but will give us unexpected output as the function does not have parameter but we provided an argument
-
-/*const num = 103;
-
-function getLastDigit() {
-  return num.toString().slice(-1);
-}
-
-console.log(`The last digit of 42 is ${getLastDigit(42)}`);
-console.log(`The last digit of 105 is ${getLastDigit(105)}`);
-console.log(`The last digit of 806 is ${getLastDigit(806)}`);*/
-
-// Now run the code and compare the output to your prediction
-// The last digit of 42 is 3
-// The last digit of 105 is 3
-// The last digit of 806 is 3
-
-// Explain why the output is the way it is
-// It is because we declared a function with no parameters so the function will ignore any arguments we provide
-// since the var num is declared and assigned with a value so every time the function is called it will use the var num
-
-// Finally, correct the code to fix the problem
-// Here is the fixed code
-function getLastDigit(num) {
-  return num.toString().slice(-1);
-}
-
-console.log(`The last digit of 42 is ${getLastDigit(42)}`);
-console.log(`The last digit of 105 is ${getLastDigit(105)}`);
-console.log(`The last digit of 806 is ${getLastDigit(806)}`);
-
-// This program should tell the user the last digit of each number.
-// Explain why getLastDigit is not working properly - correct the problem
+// Predict and explain first...
+
+// Predict the output of the following code:
+// I predict the code will run but will give us unexpected output as the function does not have parameter but we provided an argument
+
+/*const num = 103;
+
+function getLastDigit() {
+  return num.toString().slice(-1);
+}
+
+console.log(`The last digit of 42 is ${getLastDigit(42)}`);
+console.log(`The last digit of 105 is ${getLastDigit(105)}`);
+console.log(`The last digit of 806 is ${getLastDigit(806)}`);*/
+
+// Now run the code and compare the output to your prediction
+// The last digit of 42 is 3
+// The last digit of 105 is 3
+// The last digit of 806 is 3
+
+// Explain why the output is the way it is
+// It is because we declared a function with no parameters so the function will ignore any arguments we provide
+// since the var num is declared and assigned with a value so every time the function is called it will use the var num
+
+// Finally, correct the code to fix the problem
+// Here is the fixed code
+function getLastDigit(num) {
+  return num.toString().slice(-1);
+}
+
+console.log(`The last digit of 42 is ${getLastDigit(42)}`);
+console.log(`The last digit of 105 is ${getLastDigit(105)}`);
+console.log(`The last digit of 806 is ${getLastDigit(806)}`);
+
+// This program should tell the user the last digit of each number.
+// Explain why getLastDigit is not working properly - correct the problem

Sprint-3/3-mandatory-implement/1-bmi.js

@@ -1,23 +1,23 @@
-// Below are the steps for how BMI is calculated
-
-// The BMI calculation divides an adult's weight in kilograms (kg) by their height in metres (m) squared.
-
-// For example, if you weigh 70kg (around 11 stone) and are 1.73m (around 5 feet 8 inches) tall, you work out your BMI by:
-
-// squaring your height: 1.73 x 1.73 = 2.99
-// dividing 70 by 2.99 = 23.41
-// Your result will be displayed to 1 decimal place, for example '23.4'.
-
-// You will need to implement a function that calculates the BMI of someone based off their weight and height
-
-// Given someone's weight in kg and height in metres
-// Then when we call this function with the weight and height
-// It should return a string of their Body Mass Index to 1 decimal place
-
-function calculateBMI(weight, height) {
-  const BMI = weight / height ** 2;
-  const stringBMI = BMI.toString();
-  return stringBMI.slice(0, stringBMI.indexOf(".") + 2);
-}
-
-console.log(calculateBMI(70, 1.73));
+// Below are the steps for how BMI is calculated
+
+// The BMI calculation divides an adult's weight in kilograms (kg) by their height in metres (m) squared.
+
+// For example, if you weigh 70kg (around 11 stone) and are 1.73m (around 5 feet 8 inches) tall, you work out your BMI by:
+
+// squaring your height: 1.73 x 1.73 = 2.99
+// dividing 70 by 2.99 = 23.41
+// Your result will be displayed to 1 decimal place, for example '23.4'.
+
+// You will need to implement a function that calculates the BMI of someone based off their weight and height
+
+// Given someone's weight in kg and height in metres
+// Then when we call this function with the weight and height
+// It should return a string of their Body Mass Index to 1 decimal place
+
+function calculateBMI(weight, height) {
+  const BMI = weight / height ** 2;
+  const stringBMI = BMI.toString();
+  return stringBMI.slice(0, stringBMI.indexOf(".") + 2);
+}
+
+console.log(calculateBMI(70, 1.73));