refactor: reduce calculateSumAndProduct to single loop

Author: marquinacarlos

Sprint-1/JavaScript/calculateSumAndProduct/calculateSumAndProduct.js

@@ -9,21 +9,19 @@
  *   "product": 30 // 2 * 3 * 5
  * }
  *
- * Time Complexity:
- * Space Complexity:
- * Optimal Time Complexity:
+ * Time Complexity: O(n) - two passes through the array
+ * Space Complexity: O(1) - only two variables
+ * Optimal Time Complexity: O(n) - single pass through the array
  *
  * @param {Array<number>} numbers - Numbers to process
  * @returns {Object} Object containing running total and product
  */
 export function calculateSumAndProduct(numbers) {
   let sum = 0;
-  for (const num of numbers) {
-    sum += num;
-  }
-
   let product = 1;
+
   for (const num of numbers) {
+    sum += num;
     product *= num;
   }
 

Sprint-1/Python/calculate_sum_and_product/calculate_sum_and_product.py

@@ -12,20 +12,15 @@ def calculate_sum_and_product(input_numbers: List[int]) -> Dict[str, int]:
         "sum": 10, // 2 + 3 + 5
         "product": 30 // 2 * 3 * 5
     }
-    Time Complexity:
-    Space Complexity:
-    Optimal time complexity:
+    Time Complexity: O(n) - two passes through the list
+    Space Complexity: O(1) - only two variables
+    Optimal time complexity: O(n) - single pass through the list
     """
-    # Edge case: empty list
-    if not input_numbers:
-        return {"sum": 0, "product": 1}
-
-    sum = 0
-    for current_number in input_numbers:
-        sum += current_number
-
+    total = 0
     product = 1
+
     for current_number in input_numbers:
+        total += current_number
         product *= current_number
 
-    return {"sum": sum, "product": product}
+    return {"sum": total, "product": product}